如何在同一的Visual Studio调试会话作为父启动子进程，以编程？ [英] How to start a child process in the same Visual Studio debugging session as the parent, programmatically?

问题描述

在调试器下运行的过程中，我想开始在同一个调试子进程。

When running a process under the debugger, I would like to start a child process in the same debugger.

目前，我用

Process.Start("sample.exe");

我希望它是这样的：

I want it to be something like this:

if (Debugger.IsAttached)
    // start "sample.exe" in the same debugging session
else
    Process.Start("sample.exe");

我能通过一个标志，指示它来调用子进程调试.Launch（），但不会赶上启动的错误，并导致调试会话，其中有些功能没有启用（如编辑并继续等）。这是最好有调试器直接启动的过程。

I could pass a flag to the child process that instructs it to call Debugger.Launch(), but that won't catch start up errors, and it results in a debugging session where some features are not enabled (such as edit and continue, etc). It's preferable to have the debugger launch the process directly.

推荐答案

您要重视调试器来处理你开始。可以这样做：

You should attach debugger to process you are starting. This could be done:

1. 手动从Visual Studio开始SAMPLE.EXE中选择菜单调试>附加处理后..


2. 编程重视内部SAMPLE.EXE

调试
3. 的使用VS.NET自动化模型

附加到进程的
4. 更新：：您可以设置windows环境下附调试器每次SAMPLE.EXE开头：启动调试器自动（您需要无论如何调用Debugger.Break）


5. 某些外部工具也许

1. Manually from Visual Studio after starting "sample.exe" select it menu Debug > Attach to process..
2. Programmatically attach debugger inside "sample.exe"
3. Attaching to a Process using VS.NET Automation Model
4. UPDATE: You can setup windows environment to attach debugger every time "sample.exe" starts: Launch the Debugger Automatically (you will need to call Debugger.Break anyway)
5. Some external tool maybe

这里是代码SAMPLE.EXE附加调试器：（！Debugger.IsAttached）

Here is code for "sample.exe" to attach debugger:

if (!Debugger.IsAttached)
     Debugger.Launch();
Debugger.Break();

您应该通过一些参数设置为SAMPLE.EXE，以验证是否需要附加调试器。

You should pass some parameter to "sample.exe" to verify if you need to attach debugger.

Process.Start("sample.exe", "Debug=true");

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