序列化类XML? [英] Serialize class to XML?
本文介绍了序列化类XML?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有后续类和持有该列表:
I have the follow class and the list that holds it:
public class Transport
{
public string TransportType { get; set; }
public string Mode { get; set; }
public class Coordinates
{
public float ID { get; set; }
public float LocX { get; set; }
public float LocY { get; set; }
public float LocZ { get; set; }
public ObjectState State { get; set; }
public List<int[]> Connections = new <int[]>();
}
}
public enum ObjectState
{
Fly,
Ground,
Water
}
public static List<Transport> Tracking = new List<Transport>();
我如何序列化跟踪到XML?
How do I serialize the Tracking to XML ?
我知道我可以使用[Serializable接口]的名单上,序列化到文件,但我不知道我如何定义它保存为XML。
I know I can use [Serializable] on the list and serialize it to file but I am not sure on how I define it to be saved as XML.
推荐答案
如果双方你的类被标记与 [Serializable接口]
属性,然后保存的东西到一个文件应该是简单的:
If both of your classes were tagged with the [Serializable]
attribute, then saving things to a file should be as simple as:
var serializer = new XmlSerializer(typeof(Transport));
using(var writer = new StreamWriter("C:\\Path\\To\\File.xml"))
{
serializer.Serialize(writer, instance);
}
更新
对不起,不知道你问的有关如何自定义输出。这正是 [XmlAttribute]
和 [的XmlElement]
属性是:
Sorry, didn't realize you were asking about how to customize the output. That is what the [XmlAttribute]
and [XmlElement]
attributes are for:
public class Transport
{
// Store TransportType as an attrribute called Type in the XML
[XmlAttribute("Type")]
public string TransportType { get; set; }
// Rest of Implementation
}
这篇关于序列化类XML?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文