不要添加属性到接口防止创建私有/保护"设置"在派生类型？ [英] Do adding properties to an interface prevent creating private/protected "set" in derived types?

问题描述

编辑：的原来我错过了一些明显的，但我要离开，以防有人开放的问题使得其他同样明显的错误。感谢那些谁指了出来的请参阅说明底部。

是否有可能有一个非公开组被重写的接口属性属性？

Is it possible to have a non-public set on a property that is overriding an interface property?

也许我有一个愚蠢的时刻，但在我看来，其在接口中定义implicily的属性要求，没有派生

Perhaps I'm having a stupid moment, but it seems to me that having a property defined in an interface implicily requires that no deriving class may provide any non-public set for said property.

Example:

例$ C>接口IField
{
BOOL的IsValid {搞定; }
}

interface IField { bool IsValid { get; } }

...而且由于界面特性可能没有访问修饰符是指：

... and since interface properties may not have accessibility modifiers means that:

class Field : IField
{
    public override bool IsValid { get; protected set; }
}

...尽管它符合接口的事实将不可能要求概念的

IMO这有可能通过非公开性质进行了封装很大的负面影响，并防止一些共同使用patters为Propertes。

IMO this has large negative implications for encapsulation that might be done via non-public Properties, and prevents a number of common use patters for Propertes.

我知道，你可以创建修改一个共同的后备存储的非公开SetIsValid成员，但是这将创建一个不一致的格局，并添加什么本来是代码的噪音，如果不是必要的。

I'm aware that you can create a non-public SetIsValid member that modifies a common backing store, but that would create an inconsistent pattern and add what would otherwise be code noise were it not necessary.

的有我错过了什么？的

编辑：是的，我的有无的错过了什么

Yes I have missed something

我M此刻修改别人的代码，只是意识到，我被实现的接口，并从基类派生摔跤类。而我是新的C＃这是什么原因造成的覆盖混乱。

I'm modifying someone else's code at the moment and just realize that the class I was wrestling with implemented the interface and derived from a base class. And I'm new to c# That's what caused the override confusion.

实际的类看起来像：

class Field : IField, BaseField
{
    public override bool IsValid { get; protected set; }
}

...其中则baseField实现的接口为好，但没有实现设定。

...where BaseField implemented the interface as well, but did not implement the set.

推荐答案

这是完全合法的。你不需要override关键字（其实它不会编译），但并没有什么东西做这个阻止你：

This is perfectly legal. You don't need the override keyword (in fact it wouldn't compile) but there's nothing stopping you from doing this:

interface IField
{
    bool IsValid { get; }
}

class Field : IField
{
    public bool IsValid { get; protected set; }
}

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