的Flex /动作快照 [英] Flex/actionscript snapshot

问题描述

         var bmd:BitmapData = ImageSnapshot.captureBitmapData(someSprite);
         trace("bmd size "+getSize(bmd));
         var bounds:Rectangle = new Rectangle(0, 0, bmd.width, bmd.height);
     var snapshot:ImageSnapshot = new ImageSnapshot(0,0,bmd.getPixels(bounds));

         //var snapshot:ImageSnapshot = ImageSnapshot.captureImage(someSprite);
     var file:FileReference = new FileReference();
     file.save(snapshot.data,'abc.png');

在保存文件时，经过上面的code 我尝试打开它，我得到这不是一个有效的位图文件。我曾尝试2-3不同的观众。

In the above code after saving the file, when I try to open it, I get "This is not a valid bitmap file". I have tried 2-3 different viewers.

推荐答案

要延长Amarghosh的回答，期待将ImageSnapshot的构造

To extend Amarghosh's answer, look to the constructor of ImageSnapshot

ImageSnapshot(width:int, height:int, data:ByteArray, contentType:String)

在数据字段不期望的BitmapData像素数据（bmp.getPixels <$ C C $>），该公司预计，数据连接codeD在给定的的contentType 。所以，你可以这样做：

The data field isn't expecting BitmapData pixel data (bmp.getPixels), it's expecting data encoded in the given contentType. So you could do:

var encoder:PNGEncoder = new PNGEncoder();
var bytes:ByteArray = encoder.encode(bmp);
new ImageSnapshot(width, height, bytes, encoder.contentType);

在你要连接code你自己无论如何，你应该废除第二将ImageSnapshot 参考和使用：

Once you have to encode it yourself anyway, you should probably do away with the second ImageSnapshot reference and use:

new FileReference().save(bytes, "abc.png");

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