如何序列化一个C＃对象转换为XML架构没有信息？ [英] How to serialize an c# object into xml without schema info?

问题描述

这是我做过什么：

一个Serializable类：

A Serializable class:

[Serializable()]
public class Ticket
{
    public string   CitationNumber { get; set; }
    public decimal Amount { get; set; }
}

然后序列化模型转换成XML：

Then serialize a model into xml:

var model = cart.Citations
    .Select(c => new Ticket(c.Number, c.Amount)).ToList();
var serializer = new XmlSerializer(typeof (List<Ticket>));
var sw = new StringWriter();
serializer.Serialize(sw, model);
return sw.ToString();

输出 sw.ToString（）是像

<?xml version="1.0" encoding="utf-16"?>
<ArrayOfTicket xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Ticket>
<CitationNumber>00092844</CitationNumber>
<Amount>20</Amount>
</Ticket>
</ArrayOfTicket>  

有没有一种方法来定制序列化（）输出除去像那些架构信息：<？code>< XML版本=1.0编码=UTF-16> 和的xmlns ：XSI =htt​​p://www.w3.org/2001/XMLSchema-instance的xmlns：XSD =htt​​p://www.w3.org/2001/XMLSchema

Is there a way to customize the Serialize() output to remove those schema info like: <?xml version="1.0" encoding="utf-16"?> and xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"?

和如何更改根元素 ArrayOfTicket 成别的东西？

And how can I change the root element ArrayOfTicket into something else?

我必须与输出控制？

推荐答案

您需要一些XML技巧...

You need a few xml tricks...

var serializer = new XmlSerializer(typeof(List<Ticket>));

var ns = new XmlSerializerNamespaces();
ns.Add("", "");
var sw = new StringWriter();
var xmlWriter = XmlWriter.Create(sw, new XmlWriterSettings() { OmitXmlDeclaration = true });

serializer.Serialize(xmlWriter, model, ns);
string xml = sw.ToString(); 

输出：

Output:

<ArrayOfTicket>
  <Ticket>
    <CitationNumber>a</CitationNumber>
    <Amount>1</Amount>
  </Ticket>
  <Ticket>
    <CitationNumber>b</CitationNumber>
    <Amount>2</Amount>
  </Ticket>
</ArrayOfTicket>

的 PS：我添加缩进= TRUE 到 XmlWriterSettings 来得到上面的输出的

PS: I added Indent = true to XmlWriterSettings to get the above output

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