显示使用C＃中的dataGridView位图 [英] Showing a bitmap in dataGridView using C#

问题描述

我想的dataGridView显示一些图像。我有两个组成部分，的dataGridView，DataTable，并一个位图。数据表有两列。

I want to show in dataGridView some image. I have two components, dataGridView, dataTable and one Bitmap. DataTable has two columns.

dataGridview.source = dataTable;

现在，我想的dataGridView显示三列，两个来自DataTable，并新三板与我的位图。如果是比较容易的，我可以修改DataTable，并的dataGridView。

Now, I want to show in dataGridView three columns, two from dataTable and new third with my bitmap. If it is easier, I can modify dataTable and dataGridView.

是否有可能呢？

推荐答案

有几种方法你可以接近这一点。

There are several ways you can approach this.

有是一个图像列类型在DataGridView的DataGridViewImageColumn，里面有，你可以通过一个位图图像属性。

There is an image column type for the DataGridView, the DataGridViewImageColumn, which has an image property that you can pass a bitmap to.

类似下面应该工作：

private void createGraphicsColumn(Bitmap image)
{
    DataGridViewImageColumn imageColumn = new DataGridViewImageColumn();
    imageColumn.Image = image;
    imageColumn.Name = "Tree";
    imageColumn.HeaderText = "Nice tree";
    dataGridView1.Columns.Insert(2, imageColumn);
}

您还可以，如果需要设置单个单元格的Value属性在此列。

You can also set the Value property of individual cells in this column if needed.

上面的例子加上一大堆其他的讨论上可以的 MSDN 。

The example above plus a whole lot of other discussion can be found on MSDN.

另一种方法是添加映像成数据表 - 这会自动生成图像列，但在数据表需要新列的类型为字节数组

Another option is to add your image into the datatable - this will automatically generate your image column, but the new column in the datatable needs to be of type byte array.

我发现下面的代码来做到这一点快速谷歌：

I found the following code to do this with a quick google:

public byte[] imageToByteArray(System.Drawing.Image imageIn)
{
    MemoryStream ms = new MemoryStream();
    imageIn.Save(ms,System.Drawing.Imaging.ImageFormat.Gif);
    return  ms.ToArray();
}

如果你采用这种方法，我建议做一个小小的研究，以找到创建字节数组的最佳方法 - 我不能担保该代码是最好的。

If you do take this approach I'd suggest doing a little research to find the best method of creating the byte array - I couldn't vouch for that code being the best.

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