我怎样才能摆脱一个废弃的互斥？ [英] How can I get rid of an abandoned mutex?

问题描述

摘要：

有没有办法来清除如果进程互斥的？创造了它是死了

详细内容：

我用一个互斥体，以确保只有一个实例我的应用程序运行的。

I use a mutex to make sure that only one instance of my app runs.

在测试了一些新的代码（做自动更新）（0）我跑Environment.Exit。而在调试模式下运行，我的互斥体被清理的罚款。

While testing out some new code (to do auto updating) I ran Environment.Exit(0). While running in debug mode, my mutex was cleaned up fine.

但是，当我改变了构建以释放，那么互斥退出调用后保持周围，是标记为被遗弃的：

But when I changed the build to be 'Release' then the mutex stays around after the exit call and is marked as abandoned:

我有双重检查以确保没有仍在运行，该互斥附加到处理

I have double checked to make sure that there is not a process still running that this mutex is attached to.

现在每次我跑我的应用程序时，它认为互斥量仍然存在，不会推出我的应用程序。 （这也崩溃，因为它试图将消息发送到应用程序，以显示自己的正在运行实例）

Now every time I run my app, it thinks the mutex is still there and will not launch my app. (It also crashes because it tries to send a message to the "currently running" instance of the app to show itself.)

我试图把这样的互斥体：

I tried to free the mutex like this:

bool createdNew;
string applicationId = "18773:TestStudio";
var singleInstanceMutex = new Mutex(true, applicationId, out createdNew);

singleInstanceMutex.Close();  // Tried ReleaseMutex() too

但当然只是得到它andthen释放它。

but of course that just gets it andthen frees it.

我知道我可以只重启，但我跳了的情况下，这个不断发生在生产更好的修补程序。

I know I could just reboot, but I am hopping for a better fix in case this ever happens in production.

有没有办法来清除一个互斥体，如果创建它的过程是死了没有？

推荐答案

不知道这实际上回答你的问题，但这里是我为此使用的代码：

Don't know if this actually answers your question, but here's the code I use for this purpose:

  // Mutex object used to determine if there are multiple instances of this program running. 
  //  Note that this is a reference to a .Net Mutex object, not the Windows mutex itself.
  private static Mutex _onlyOneInstanceMutex;



  /// <summary>
  /// Method to test that there is not another instance of the program already running on this 
  /// machine, or at least in this Terminal Services session or Windows Vista / Windows 7 
  /// concurrent sessions session. If there is, a message box-style localized error message is 
  /// displayed and the value false is returned. This implies that this method should not be 
  /// used in programs that are run as a Windows service.
  /// 
  /// This implementation uses a .Net Mutex object in public storage to prevent it from being 
  /// garbage-collected. The name of the associated Windows mutex is simply the program name as 
  /// provided by the caller. Neither the .Net Mutex object nor the Windows mutex are ever 
  /// explicitly released; they remain in existence, perhaps in an "abandoned" state, until the 
  /// process that created them terminates.
  /// </summary>
  /// <returns>false if another instance running, otherwise true</returns>
  [SuppressMessage("Microsoft.Reliability", "CA2004:RemoveCallsToGCKeepAlive",
                   Justification = "Not sure if this is correct or not.")]
  public static bool TestOnlyOneInstance(string programName)
  {
     // Funny construct to prevent the Mutex from being garbage collected
     GC.KeepAlive(_onlyOneInstanceMutex);

     // Test if we are the first instance, and if so create the Windows mutex, making it 
     //  impossible for subsequent instances to successfully create their mutex
     bool firstInstance;
     _onlyOneInstanceMutex = new Mutex(false, programName, out firstInstance);
     if (firstInstance)
        return true;

     // Display a (possibly localized) error message, then return
     string errorMessage = MLocalizer.GetString("Error1", 
           "Another instance of this program is already running on this machine.") +
         "\n" + MLocalizer.GetString("Error2",
                                     "You cannot run two instances at the same time.") +
         "\n" + MLocalizer.GetString("Error3", "Please use the other instance.");
     MessageBox.Show(errorMessage, programName, MessageBoxButtons.OK, MessageBoxIcon.Error);
     return false;
  }

编辑：

唯一的区别我可以在我的代码中看到的和你们的是，我指定最初拥有的为假的，我对垃圾收集的有趣的事情。

Only differences I can see in my code and yours is that I specify "initially owned" as false, and I have the funny thing about the garbage collection.

呵呵，我宣布互斥静态的。

Oh, and I declare the Mutex static.

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