C＃/ LINQ的：在一个IEnumerable应用映射函数的每个元素？ [英] C#/Linq: Apply a mapping function to each element in an IEnumerable?

问题描述

我一直在寻找一种方式来IEnumerable的每个元素转换成其它东西使用映射功能（在一个LINQ兼容的方式），但我没有发现任何东西。

I've been looking for a way to transform each element of an IEnumerable into something else using a mapping function (in a Linq-compatible way) but I haven't found anything.

对于一个（简单）的例子，它应该能够做到像

For a (very simple) example, it should be able to do something like

IEnumerable<int> integers = new List<int>() { 1, 2, 3, 4, 5 };
IEnumerable<string> strings = integers.Transform(i => i.ToString());

但我没有发现任何东西。我的意思是，这是非常简单的编写完成了一个扩展方法（基本上，所有它需要被包装源枚举到一个新的类，然后写一点样板代码委派的调用），但我本来期望这是一个相当基本的操作，写我自己感觉就像重新发明轮子 - 我不能动摇的感觉，有可能是我应该使用一个内置的方式，我一直没盲目看吧。

But I haven't found anything. I mean, it's pretty straightforward to write an extension method that accomplishes that (basically, all it requires is wrapping the source enumerator into a new class and then writing a bit of boilerplate code for delegating the calls to it), but I would have expected this to be a fairly elementary operation, and writing it myself feels like reinventing the wheel - I can't shake the feeling that there may be a built-in way which I should be using, and I've just been too blind to see it.

所以......是有什么在LINQ的，让我做什么上述我？

So... is there something in Linq that allows me to do what I described above?

推荐答案

您可以只使用 选择（ ） 扩展方法：

You can just use the Select() extension method:

IEnumerable<int> integers = new List<int>() { 1, 2, 3, 4, 5 };
IEnumerable<string> strings = integers.Select(i => i.ToString());

或在LINQ语法：

IEnumerable<int> integers = new List<int>() { 1, 2, 3, 4, 5 };

var strings = from i in integers
              select i.ToString();

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