Lambda\Anonymous函数作为参数 [英] Lambda\Anonymous Function as a parameter
问题描述
我是一个很新的C#。只是玩弄它。不是一个真正的目的。
无效makeOutput(INT加上_Param)
{
Console.WriteLine(加上_Param,的ToString());
}
// ...
//某处在代码
{
makeOutput(/ *为例子有些不是C#代码是什么我想* /函数:int(){返回0;});
}
是否有可能使用一个真正的匿名函数(指返回结果)<? / p>
我不希望使用委托,如
//某处在代码
{
Func键< INT> X =()=> {返回0; };
makeOutput(X())
}
此外,我不要想改变方法的参数类型,如
无效makeOutput(Func键< INT>加上_Param)
{
}
这是很常见的决定。
一切正常。我只知道,我想是不可能的事情。我想声明匿名函数,并在同一个地方执行。注意:直接宣告,没有通用包装器直接调用
//类似Flash(AS3)代码///无法编译
makeOutput((函数:int(){返回0;})());
是的。结果
这就是所谓的。委托
委托是(更多或更少)的正常类型;你可以将它们传递给函数就像任何其他类型的
无效MakeOutput(Func键< INT>参数){
Console.WriteLine(参数());
}
makeOutput(代表{返回4;});
makeOutput(()=> {返回4;});
makeOutput(()=→4);
您修改的ED问题是没有意义的。
C#是类型安全的。结果
如果该方法不希望一个函数作为参数,你不能给它一个方法作为参数
I'm a very new to C#. Just playing around with it. Not for a real purpose.
void makeOutput( int _param)
{
Console.WriteLine( _param.ToString());
}
//...
// Somewhere in a code
{
makeOutput( /* some not c# code for an example for what do I want */ function : int () { return 0; } );
}
Is it possible to use a REAL anonymous functions (means returning result)?
I do not want to use delegates such as
// Somewhere in a code
{
Func<int> x = () => { return 0; };
makeOutput( x())
}
Also I DO NOT want to change method parameter type such as
void makeOutput( Func<int> _param)
{
}
That is very common decision.
Everything is alright. I just understood that I wanted impossible things. I wanted to declare anonymous function and execute it in the same place. Note: DIRECT declaring and DIRECT call without generic wrapper.
// flash-like (as3) code /// DOES NOT COMPILE
makeOutput( (function : int(){ return 0; })() );
Yes.
It's called a delegate.
Delegates are (more-or-less) normal types; you can pass them to functions just like any other type.
void MakeOutput(Func<int> param) {
Console.WriteLine(param());
}
makeOutput(delegate { return 4; });
makeOutput(() => { return 4; });
makeOutput(() => 4);
Your edited question does not make sense.
C# is type-safe.
If the method doesn't want a function as a parameter, you cannot give it a method as a parameter.
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