如何添加此方法扩展方法到我的类的属性？ [英] How can I add this method as an extension method to properties of my class?

问题描述

我有一个方法，我想添加这个方法扩展方法我类的属性。
该方法给出一个表达式作为输入参数。该方法是象下面这样：

I have a method and I want to add this method as an extension method to properties of my class. This method give an expression as input parameter. The method is like below :

    public static string GetPropertyName<T>(Expression<Func<T>> propertyExpression)
    {
        return (propertyExpression.Body as MemberExpression).Member.Name;
    }

我想用这个方法就像下面的例子：

I want to use this method like below example :

string propertyName = MyClass.Property1.GetPropertyName();

这可能吗？如果是，该如何解决？

Is it possible? if yes, what is the solution?

推荐答案

没有，这是不可能做到这一点。目前尚不清楚是否 MyClass的是一个类的名称（ Property1 是一个静态属性）还是它的一个实例财产和 MyClass.Property1 根本就不是一个有效的成员访问。如果是后者，你可能想改变你的方法是这样的：

No, it's not possible to do that. It's not clear whether MyClass is the name of a class (and Property1 is a static property) or whether it's an instance property and MyClass.Property1 simply isn't a valid member access. If it's the latter, you probably want to change your method to something like:

public static string GetPropertyName<TSource, TResult>(
    Expression<Func<TSource, TResult>> propertyExpression)
{
    return (propertyExpression.Body as MemberExpression).Member.Name;
}

和称呼其为：

string propertyName = GetPropertyName<MyClass, string>(x => x.Property1);

或者你的可能的使用通用类与通用的方法，使字符串可以推断出：

Or you could use a generic class with a generic method, so that string can be inferred:

string propertyName = PropertyUtil<MyClass>.GetPropertyName(x => x.Property1);

这会是这样的：

public static class PropertyUtil<TSource>
{
    public static string GetPropertyName<TResult>(
        Expression<Func<TSource, TResult>> propertyExpression)
    {
       return (propertyExpression.Body as MemberExpression).Member.Name;
    }
}

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