转换成INT字符串的字符一定长度 [英] convert int into string with certain length of char

问题描述

如果标题不清晰，生病尝试以及在这里解释它。我有一大堆的整数，从1到999，我需要将这些转换成字符串，但是当我做到这一点，我需要他们3个字符长。因此，举例来说，如果我有：

  INT I1 = 45;当我把那转化为字符串，我需要这种
  

然后： 045或类似的，如果我有8的整数，那么，将有变成008，如果有什么有3个地方如143，那么它也只是输出为143这是容易做到？

感谢您提前反应。 ：）

解决方案

 字符串输出= someInt.ToString（000）; 
  

如果您想使它更有活力，你会做这样的事情。

  //其中'长'是3 
字符串输出= someInt.ToString（新的字符串（0，长度））; 
 //或
字符串输出= i.ToString（）PadLeft（长度，'0'）; 
  

If the title wasn't clear, ill try to explain it well here. I have a bunch of integers, ranging from 1 to 999, and i need to convert these into strings, but when i do that, i need them to be 3 characters long. so for instance, if i had:

int i1 = 45;

then when i turned that into a string, i'd need this: "045" or similarly, if i had an int of 8 then that would have to turn into "008", and if anything had 3 places, such as 143, then it would just be outputted as 143. is this easily possible?

Thanks for responses in advance. :)

解决方案

string output = someInt.ToString("000");

If you would like to make it more dynamic, you would do something like this

// where 'length' is 3
string output = someInt.ToString(new string('0', length));
// or 
string output = i.ToString().PadLeft(length, '0');

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