如何使用&放大器;运营商在C＃中？是代码正确的翻译？ [英] How to use the & operator in C#? Is the the translation of the code correct?

问题描述

行如果（ARG2&安培; 1）C ++（Arg2为DWORD）等于如果（ARG2&安培; 1 == 0）？在C＃（ARG2是UINT32），右

the line "if(arg2 & 1)" in C++(arg2 is DWORD) is equal to "if(arg2 & 1==0)" in C#(arg2 is Uint32),right?

我想转换从C ++到C＃功能，但我得到一个错误：

I am trying to translate a function from C++ to C#,but I get an error:

Operator '&' cannot be applied to operands of type 'uint' and 'bool'

我会还感激，如果你能在任何其他错误整体功能进一步看到的。

I'd be also thankful if you could see further in the whole function for any other mistakes.

C ++

DWORD Func_X_4(DWORD arg1, DWORD arg2, DWORD arg3)
{
LARGE_INTEGER result = {1, 0};
LARGE_INTEGER temp1 = {0};
LARGE_INTEGER temp2 = {0};
LARGE_INTEGER temp3 = {0};
LARGE_INTEGER temp4 = {0};
for(int x = 0; x < 32; ++x)
{
	if(arg2 & 1)
	{
		temp1.LowPart = arg3;
		temp1.HighPart = 0;
		temp2.QuadPart = temp1.QuadPart * result.QuadPart;
		temp3.LowPart = arg1;
		temp3.HighPart = 0;
		temp4.QuadPart = temp2.QuadPart % temp3.QuadPart;
		result.QuadPart = temp4.QuadPart;
	}
	arg2 >>= 1;
	temp1.LowPart = arg3;
	temp1.HighPart = 0;
	temp1.QuadPart *= temp1.QuadPart;
	temp2.LowPart = arg1;
	temp2.HighPart = 0;
	temp3.QuadPart = temp1.QuadPart % temp2.QuadPart;
	arg3 = temp3.LowPart;
	if(!arg2)
		break;
}
return result.LowPart;
}

转换为C＃

Converted to C#

LARGE_INTEGER结构：

LARGE_INTEGER structure:

[StructLayout(LayoutKind.Explicit, Size = 8)]
public struct LARGE_INTEGER
{
    [FieldOffset(0)]
    public Int64 QuadPart;
    [FieldOffset(0)]
    public UInt32 LowPart;
    [FieldOffset(4)]
    public Int32 HighPart;
}

功能：

Function:

public static UInt32 X4(UInt32 arg1, UInt32 arg2, UInt32 arg3)
    {
        LARGE_INTEGER result = new LARGE_INTEGER();
        result.LowPart = 1;
        result.HighPart = 0;
        LARGE_INTEGER temp1 = new LARGE_INTEGER();
        LARGE_INTEGER temp2 = new LARGE_INTEGER();
        LARGE_INTEGER temp3 = new LARGE_INTEGER();
        LARGE_INTEGER temp4 = new LARGE_INTEGER();
        for (int x = 0; x < 32; ++x)
        {
            if (arg1 & 1 ==0)
            {
                temp1.LowPart = arg3;
                temp1.HighPart = 0;
                temp2.QuadPart = temp1.QuadPart * result.QuadPart;
                temp3.LowPart = arg1;
                temp3.HighPart = 0;
                temp4.QuadPart = temp2.QuadPart % temp3.QuadPart;
                result.QuadPart = temp4.QuadPart;
            }
            arg2 >>= 1;
            temp1.LowPart = arg3;
            temp1.HighPart = 0;
            temp1.QuadPart *= temp1.QuadPart;
            temp2.LowPart = arg1;
            temp2.HighPart = 0;
            temp3.QuadPart = temp1.QuadPart % temp2.QuadPart;
            arg3 = temp3.LowPart;
            if (arg2==0)
                break;
        }
        return result.LowPart;
    }

这是我还没有确定：

1. 不管是C ++中的DWORD是UInt32的或的Int32在C＃


2. 如果（整数安培;整数）？意味着如果（整数和整数== 0）？ //这是我上述错误的放置位置。


3. 如果（！整数），如果是指（整数！= 0）？


4. 为什么运营商和放大器;不能在C＃逻辑地使用，这意味着它需要一个布尔？


5. LARGE_INTEGER结果= {1,0}指result.lowpart是1和result.highpart是0或result.Quadpart = 1？

1. Whether a DWORD in C++ is UInt32 or Int32 in C#?
2. if(integer & integer) means if(integer and integer ==0)? //this is where the error i described above is placed.
3. if(!integer) means if(integer != 0)?
4. Why operator & cannot be used logically in C# ,meaning it requires a boolean?
5. "LARGE_INTEGER result = {1, 0}" means result.lowpart is 1 and result.highpart is 0 or result.Quadpart = 1?

在此先感谢！

推荐答案

您写的：

如果（ARG1&安培; ARG2 == 0）

if (arg1 & arg2==0)

编译理解：

if (arg1 & (arg2==0))

您应该写：

if ((arg1 & arg2) == 0)

这是C ++的语句应该被翻译成C＃的方式：

This is the way the C++ statement should be translated to C# :

if (arg2 & 1) // C++ (arg2 is DWORD)
if ((arg2 & 1) != 0) // C# (arg2 is Uint32)

或者，在一个更​​通用的方法！

Or, in a more generic way:

if (Flags & FlagToCheck) // C++
if ((Flags & FlagToCheck) != 0) // C#

---

在C / C ++，0是假的，其他的一切都是真实的。

In C/C++, 0 is false, everything else is true.

1. 您应该检查DWORD的定义，它应该是（无符号INT），这是UInt32的在C＃


2. 如果（整数放大器;整数），在C / C ++的意思是如果按位和两个整数之间的结果不为0（0是假的，一切是如此）。


3. 如果（！整数）意味着，如果（整数== 0）（同样，0是假的，其他的一切都是真实的）


4. 在C＃中，就像在Java中，我认为，布尔和数字是两回事，你只能用在布尔if语句，不存在隐式转换，如果你使用int：它不会编译


5. 我将离开这个给别人，我。 ð需要测试，以确保...

1. You should check the definition of DWORD, it should be (unsigned int), which is UInt32 in C#
2. if (integer & integer), in C/C++ means "if the result of the bitwise and between the two integers is not 0" (0 is false, everything else is true).
3. if (!integer) means if (integer == 0) (again, 0 is false, everything else is true)
4. in C#, like in Java I think, booleans and numbers are two different things, you can only use booleans in "if" statements, there is not implicit conversion if you use an int : it won't compile.
5. I'll leave this one to someone else, I'd need to test to be sure...

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