的SerialPort的WriteLine文本错误 [英] Serialport writeline textbox error

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本文介绍了的SerialPort的WriteLine文本错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我用来测试我的程序虚拟COM端口。我想与COM8串行写和COM9串行读。当想写从TextBox1的价值观,我得到这个错误:

  IOException异常是未处理(参数不正确)

我如何摆脱呢?

 使用系统; 
使用System.Collections.Generic;
使用System.ComponentModel;
使用System.Data这;
使用System.Drawing中;
使用System.Linq的;
使用System.Text;使用System.Threading.Tasks
;使用System.Windows.Forms的
;使用System.IO.Ports
;

命名空间Flowerpod_User_Interface
{
公共部分Form1类:表格
{
公共Form1中()
{

的InitializeComponent();
//有效的COM端口
的foreach(字符串s在System.IO.Ports.SerialPort.GetPortNames())
{
comboBox1.Items.Add的节目列表(S) ;
}
}

私人无效textBox1_TextChanged(对象发件人,EventArgs五)
{

}

私人无效Form1_Load的(对象发件人,EventArgs五)
{

}

私人无效的button1_Click(对象发件人,EventArgs五)
{
如果(serialPort1.IsOpen)
{
serialPort1.WriteLine(textBox1.Text);


}
,否则
{
MessageBox.Show(SerialPort1不开);
}
}

私人无效comboBox1_SelectedIndexChanged(对象发件人,EventArgs五)
{

}

私人无效Connect_Click(对象发件人,EventArgs五)
{
如果
{
serialPort1.PortName = comboBox1.SelectedItem.ToString()(serialPort1.IsOpen!);

serialPort1.Open();

textBox3.Text =打开;
}

}

私人无效textBox3_TextChanged(对象发件人,EventArgs五)
{

}

私人无效textBox2_TextChanged(对象发件人,EventArgs五)
{

}

私人无效button3_Click(对象发件人,EventArgs五)
{
随机slumpGenerator =新的随机();
//或者你想...下一页()返回一个双
INT TAL = slumpGenerator.Next(1000,10000)的任何限制;
textBox1.Text = tal.ToString();
}

私人无效textBox4_TextChanged(对象发件人,EventArgs五)
{

}




私人无效serialPort1_DataReceived(对象发件人,SerialDataReceivedEventArgs E)
{

}

私人无效button4_Click(对象发件人,EventArgs五)
{
如果(serialPortRead.IsOpen!)
{
serialPort1.PortName =COM9;

serialPortRead.Open();

textBox4.Text = serialPortRead.ReadLine();
}
}
}
}


解决方案

有没有这两个端口造成的问题之间的桥梁。虚拟COM端口软件骗我!


I use virtual COM ports for testing my program. I want to Serial Write with COM8 and Serial read with COM9. When a want to write the values from textbox1, i get this error:

IOException was unhandled (The parameter is incorrect) 

How do i get rid of this?

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO.Ports;

namespace Flowerpod_User_Interface
{
    public partial class Form1 : Form
    {
        public Form1()
        {

            InitializeComponent();
            // show list of valid COM ports
            foreach (string s in System.IO.Ports.SerialPort.GetPortNames())
            {
                comboBox1.Items.Add(s);
            }
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {

        }

        private void Form1_Load(object sender, EventArgs e)
        {

        }

        private void button1_Click(object sender, EventArgs e)
        {
            if (serialPort1.IsOpen)
            {
                serialPort1.WriteLine(textBox1.Text);


            }
            else
            {
                MessageBox.Show("SerialPort1 is not open");
            }
        }

        private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
        {

        }

        private void Connect_Click(object sender, EventArgs e)
        {
            if (!serialPort1.IsOpen)
            {
                serialPort1.PortName = comboBox1.SelectedItem.ToString();

                serialPort1.Open();

                textBox3.Text = "Open"; 
            }

        }

        private void textBox3_TextChanged(object sender, EventArgs e)
        {

        }

        private void textBox2_TextChanged(object sender, EventArgs e)
        {

        }

        private void button3_Click(object sender, EventArgs e)
        {
            Random slumpGenerator = new Random();
            // Or whatever limits you want... Next() returns a double
            int tal = slumpGenerator.Next(1000, 10000);
            textBox1.Text = tal.ToString();
        }

        private void textBox4_TextChanged(object sender, EventArgs e)
        {

        }




     private void serialPort1_DataReceived(object sender,SerialDataReceivedEventArgs e)
        {

        }

        private void button4_Click(object sender, EventArgs e)
        {
            if (!serialPortRead.IsOpen)
            {
                serialPort1.PortName = "COM9";

                serialPortRead.Open();

                textBox4.Text = serialPortRead.ReadLine();                 
            }
        }
    }
}

解决方案

There wasn't any bridge between the two ports which caused the problem. The virtual COM port software tricked me !.

这篇关于的SerialPort的WriteLine文本错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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