从文本文件加载JSON数据流为对象C＃ [英] Load JSON data stream from text file into objects C#

问题描述

我使用 Newtonsoft.Json.Linq ，我想加载数据到对象（或结构），我定义并把对象变成列表或集合。

目前我拉出JSON性能与索引。名字

  =文件名openFileDialog1.FileName; 
 
 StreamReader的重新= File.OpenText（文件名）; 
 JsonTextReader读卡器=新JsonTextReader（重新）; 
串克拉=; 
 
 JArray根= JArray.Load（读卡器）; 
的foreach（JObject o在根目录）
 {
 CT + =\r\\\
HACCstudentBlogs.Add（\+（串）O [全名] +\\ \\，\\）;; 
} 
 namesText.Text =克拉; 
  

对象定义如下，有时JSON将不包含一个属性值：

 类blogEntry 
 {
公共字符串ID {搞定;组; } 
公共字符串ContributorName {搞定;组; } 
公共字符串名称{搞定;组; } 
公共字符串描述{搞定;组; } 
公共字符串CreatedDate {搞定;组; } 
} 
  

解决方案

您可以使用 JsonConvert.DeserializeObject< T> ：

  [TestMethod的] 
公无效CanDeserializeComplicatedObject（）
 {
变种进入=新BlogEntry 
 {
 ID =0001，
 ContributorName =乔，
 CreatedDate =系统.DateTime.UtcNow.ToString（），
标题=＃1测试，
说明=测试的博客文章
}; 
 
 JSON字符串= JsonConvert.SerializeObject（输入）; 
 
 VAR outObject = JsonConvert.DeserializeObject< BlogEntry>（JSON）; 
 
 Assert.AreEqual（entry.ID，outObject.ID）; 
 Assert.AreEqual（entry.ContributorName，outObject.ContributorName）; 
 Assert.AreEqual（entry.CreatedDate，outObject.CreatedDate）; 
 Assert.AreEqual（entry.Title，outObject.Title）; 
 Assert.AreEqual（entry.Description，outObject.Description）; 
} 
  

I'm using Newtonsoft.Json.Linq and I'd like to load the data into objects (or structs) that I define and put the objects into a list or collection.

Currently I'm pulling out the JSON properties with indexes to the names.

filename = openFileDialog1.FileName;

StreamReader re = File.OpenText(filename);
JsonTextReader reader = new JsonTextReader(re);
string ct = "";

JArray root = JArray.Load(reader);
foreach (JObject o in root)
{
    ct += "\r\nHACCstudentBlogs.Add(\"" + (string)o["fullName"] + "\",\"\");";
}
namesText.Text = ct;

The object is defined as follows, and sometimes the JSON won't contain a value for a property:

class blogEntry
{
    public string ID { get; set; }
    public string ContributorName { get; set; }
    public string Title { get; set; }
    public string Description { get; set; }
    public string CreatedDate { get; set; }
}

解决方案

You can use JsonConvert.DeserializeObject<T>:

[TestMethod]
public void CanDeserializeComplicatedObject()
{
    var entry = new BlogEntry
    {
        ID = "0001",
        ContributorName = "Joe",
        CreatedDate = System.DateTime.UtcNow.ToString(),
        Title = "Stackoverflow test",
        Description = "A test blog post"
    };

    string json = JsonConvert.SerializeObject(entry);

    var outObject = JsonConvert.DeserializeObject<BlogEntry>(json);

    Assert.AreEqual(entry.ID, outObject.ID);
    Assert.AreEqual(entry.ContributorName, outObject.ContributorName);
    Assert.AreEqual(entry.CreatedDate, outObject.CreatedDate);
    Assert.AreEqual(entry.Title, outObject.Title);
    Assert.AreEqual(entry.Description, outObject.Description);
}

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