如何让用户从控制台上输入变量的任何金额 [英] How to let the user enter any amount of variable from Console
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问题描述
这是我做了,直到一对出现的滚动两个骰子的代码。
我的问题是,有没有对用户输入的骰子任何金额他/她想要?
我不希望创建50 INT方式骰子。如果我使用一个数组或列表我有同样的问题。我不得不为每个阵列部分numbergen 50次以上。也许有我丢失的东西?
静态无效的主要(字串[] args)
{
随机numbergen =新的随机();
INT dice1 = 0;
INT dice2 = 1;
为(INT计数器= 0;反< = 1;计数器++)
{
,而(!dice1 = dice2)
{
dice1 = numbergen.Next( 1,7);
dice2 = numbergen.Next(1,7);
如果(dice1 == dice2)
{
Console.ForegroundColor = ConsoleColor.Yellow;
Console.WriteLine(dice1 +\t+ dice2);
计数器++;
dice1 = 0;
dice2 = 1;
}
,否则如果(dice1 = dice2!)
{
Console.ForegroundColor = ConsoleColor.White;
Console.WriteLine(dice1 +\t+ dice2);
}
如果(反== 1)
{
中断;
}
}
}
到Console.ReadLine();
}
解决方案
下面是一个。版本,所有模具必须匹配
使用系统;
命名空间戴雪
{
类节目
{
静态无效的主要(字串[] args)
{
INT numberOfDice ;
//检查并检索用户想要骰子的数量。
如果(args.Length!= 1 ||!int.TryParse(参数[0],出numberOfDice))
{
Console.WriteLine(请提供骰子的数量。 );
的回报; //退出,因为阿根廷没有提供
}
//必须至少有一个,并设置一些任意的上限
如果(numberOfDice< 1 || numberOfDice→50)
{
Console.WriteLine(请提供一个数字1和50之间骰子的);
的回报; //存在,因为不是在有效范围内
}
变种骰子=新的INT [numberOfDice] //创建模具阵列(整型)
变种兰特=新的随机();
VAR匹配= FALSE; //使用虚假的开始(匹配尚未发现)
,而//循环,直到比赛成为真正的
{
VAR消息=的String.Empty(比赛!);
匹配= TRUE; //假设匹配,直到东西不匹配
(VAR I = 0; I< numberOfDice;我++)
{
//索引与初始化骰子我随机数
骰子由[i] = rand.Next(1,7);
//建行的消息写入到控制台
+消息=骰子[I] //先加模的数量
如果(I< numberOfDice - 1)
+消息=\t; //如果不是在末尾添加标签
//检查以前的模具(除第一期培训班的)具有不同数量的
如果(我大于0&安培; &安培;!骰子[我 - 1] =骰子[I])
匹配= FALSE; //嗯哦,不是所有的比赛。我们必须继续前进
}
//打印出消息
Console.ForegroundColor =匹配? ConsoleColor.Yellow:ConsoleColor.White;
Console.WriteLine(消息);
}
到Console.ReadLine();
}
}
}
This is the code that I have made that rolls two dice until a pair appear. My question is, is there a way for the user to enter any amount of dice he/she wants?
I don't want to create 50 int dice. If I use an array or List I would have the same problem. I'd have to assign each array section to numbergen 50 or more times. Maybe there is something I am missing?
static void Main(string[] args)
{
Random numbergen = new Random();
int dice1=0;
int dice2=1;
for (int counter = 0; counter <= 1; counter++)
{
while (dice1 != dice2)
{
dice1 = numbergen.Next(1, 7);
dice2 = numbergen.Next(1, 7);
if (dice1 == dice2)
{
Console.ForegroundColor = ConsoleColor.Yellow;
Console.WriteLine(dice1 + "\t" + dice2);
counter++;
dice1 = 0;
dice2 = 1;
}
else if (dice1 != dice2)
{
Console.ForegroundColor = ConsoleColor.White;
Console.WriteLine(dice1 + "\t" + dice2);
}
if (counter ==1 )
{
break;
}
}
}
Console.ReadLine();
}
解决方案
Here's a version where all die must match.
using System;
namespace Dicey
{
class Program
{
static void Main(string[] args)
{
int numberOfDice;
// check for and retrieve the number of dice the user wants.
if (args.Length != 1 || !int.TryParse(args[0], out numberOfDice))
{
Console.WriteLine("Please provide the number of dice.");
return; // exit because arg not provided
}
// Must have at least one and set some arbitrary upper limit
if (numberOfDice < 1 || numberOfDice > 50)
{
Console.WriteLine("Please provide a number of dice between 1 and 50");
return; // exist because not in valid range
}
var dice = new int[numberOfDice]; // create array of die (ints)
var rand = new Random();
var match = false; // start with false (match not found yet)
while (!match) // loop until match becomes true
{
var message = string.Empty;
match = true; // assume match until something doesn't match
for (var i = 0; i < numberOfDice; i++)
{
// initialize dice at index i with the random number
dice[i] = rand.Next(1, 7);
// build the message line to write to the console
message += dice[i]; // first add the die's number
if (i < numberOfDice - 1)
message += "\t"; // if not at the end, add a tab
// check if the previous die (except for the first of course) has a different number
if (i > 0 && dice[i - 1] != dice[i])
match = false; // uh oh, not all match. we have to keep going
}
// print out the message
Console.ForegroundColor = match ? ConsoleColor.Yellow : ConsoleColor.White;
Console.WriteLine(message);
}
Console.ReadLine();
}
}
}
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