如果存在装配C＃的条件编译 [英] C# conditional compilation if assembly exists

问题描述

我有可能或可能不存在的基准的项目。我有一个使用的参考代码，我想如果大会存在只编译它。我沿着线思维的内容：

I have a project with a reference that may or may not exist. I have code that uses that reference and I'd like to compile it only if the assembly exists. I'm thinking something along the lines of:

#if ASSEMBLY_EXISTS
    AssemblyClass.DoSomething();
#endif

根据需要，我可以在顶部和注释/取消注释放的#define ，但我更喜欢它是否能不知怎么竟知道的，如果它有没有我的人工干预，这使我相信，＃如果不会为这种情况下工作。有另一种方式的基础上是否存在装配条件编译

I could put a #define at the top and comment/uncomment as needed, but I'd prefer if it could just somehow know if it's there without my manual intervention, which leads me to believe that #if won't work for this situation. Is there another way to conditionally compile based on whether an assembly exists?

推荐答案

也许里面MSBUILD条件做;

Maybe do it with a condition inside MSBUILD;

它看起来像它

<PropertyGroup>
     <DefineConstants Condition="Exists('my.dll') ">$(DefineConstants);DLLEXISTS</DefineConstants>
</PropertyGroup>

和应该去很远倒在你的.csproj的文件。

and should go quite far down in your .csproj file.

这读取，大致为通过附加DLLEXISTS重新定义的常量，如果my.dll存在

This reads, roughly, as "redefine the constants by appending DLLEXISTS, if my.dll exists"

现在，你应该能够做到

#if DLLEXISTS
    // your stuff here
#endif

您可能需要反复折腾存在表达式找到一个合适的相对路径。

You might need to fiddle around with the EXISTS expression to find an appropriate relative path.

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