C＃作为回报仅得到读的变量;组; [英] C# return a variable as read only from get; set;

问题描述

我发誓，我已经看到了这样的一个例子，但已经被google搜索了一下，能不能找到它。

I swear I have seen an example of this but have been googling for a bit and can not find it.

我有了一个引用的类对象并需要有一个GET;方法吧。我的问题是，我不希望任何人能够与它摆弄，即我希望他们能够得到一个只读版本的它，（请注意我需要能够从我的类中改变它）。

I have a class that has a reference to an object and need to have a GET; method for it. My problem is that I do not want anyone to be able to fiddle with it, i.e. I want them to get a read only version of it, (note I need to be able to alter it from within my class).

感谢

推荐答案

没有，有没有这样做的方式。举例来说，如果你返回一个列表<字符串方式> （它不是一成不变的），然后调用者的将会的可以添加的条目

No, there's no way of doing this. For instance, if you return a List<string> (and it's not immutable) then callers will be able to add entries.

正常办法解决这是返回一个不可变的包装，如： ReadOnlyCollection还< T>

The normal way round this is to return an immutable wrapper, e.g. ReadOnlyCollection<T>.

有关其他可变类型，您可能需要返回之前克隆的价值。

For other mutable types, you may need to clone the value before returning it.

请注意，只是返回一个不可变接口视图（如返回的IEnumerable< T> 而不是列表< T> ）将不会停止铸造呼叫者。回到可变类型和变异

Note that just returning an immutable interface view (e.g. returning IEnumerable<T> instead of List<T>) won't stop a caller from casting back to the mutable type and mutating.

编辑：注意从别的，除了，这种担心也是为什么不变类型更容易推理的原因之一代码：）

Note that apart from anything else, this kind of concern is one of the reasons why immutable types make it easier to reason about code :)

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