T必须是contravariantly有效 [英] T must be contravariantly valid
本文介绍了T必须是contravariantly有效的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
什么是不对的。
interface IRepository<out T> where T : IBusinessEntity
{
IQueryable<T> GetAll();
void Save(T t);
void Delete(T t);
}
它说:
It says:
无效差异:类型参数'T'必须是'MyNamespace.IRepository.Delete(T)contravariantly有效。 'T'是协变
Invalid variance: The type parameter 'T' must be contravariantly valid on 'MyNamespace.IRepository.Delete(T)'. 'T' is covariant.
推荐答案
考虑会发生什么,如果编译器允许的:
Consider what would happen if the compiler allowed that:
interface IR<out T>
{
void D(T t);
}
class C : IR<Mammal>
{
public void D(Mammal m)
{
m.GrowHair();
}
}
...
IR<Animal> x = new C();
// legal because T is covariant and Mammal is convertible to Animal
x.D(new Fish()); // legal because IR<Animal>.D takes an Animal
和你只是想上长出头发一条鱼。
And you just tried to grow hair on a fish.
停止是指T的输出位置仅用于。您正在使用它输入位置。
The "out" means "T is only used in output positions". You are using it in an input position.
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