通过XmlReader中的XML元素解析 [英] Parsing through XML elements in XmlReader

查看:193
本文介绍了通过XmlReader中的XML元素解析的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我建设,需要通过一个XML提要运行一个应用程序,但我有与得到的某些元素有点麻烦了。

I'm building an application that needs to run through an XML feed but I'm having a little trouble with getting certain elements.

我使用的 Twitter的饲料,并希望通过所有的<运行;项目> 元素。我可以连接罚款,并从进料的内容,但我无法弄清楚如何选择时,我通过 loopuing只有项目元素reader.Read();!

I'm using the Twitter feed and want to run through all the <item> elements. I can connect fine and get the content from the feed but I can't figure out how to select only the item elements when I'm loopuing through reader.Read();.

感谢您的帮助。

推荐答案

要做到这一点,最简单的方法是使用XPath。 。榜样

The easiest way to do that is to use XPath. Example to follow.

 string xml = @"<?xml version=""1.0"" encoding=""UTF-8""?>
<rss version=""2.0"">
    <channel>
    <title>Twitter public timeline</title>
    <link>http://twitter.com/public_timeline</link>
    <description>Twitter updates from everyone!</description>
    <language>en-us</language>
    <ttl>40</ttl>

    <item>
      <title>yasu_kobayashi: rTwT: @junm : yayaya</title>
      <description>yasu_kobayashi: rTwT: @junm : yayaya</description>
      <pubDate>Tue, 28 Oct 2008 12:04:48 +0000</pubDate>
      <guid>http://twitter.com/yasu_kobayashi/statuses/978829930</guid>
      <link>http://twitter.com/yasu_kobayashi/statuses/978829930</link>

    </item><item>
      <title>FreeGroup: WikiFortio - foobar http://tinyurl.com/5gvttf</title>
      <description>FreeGroup: WikiFortio - foobar
      http://tinyurl.com/5gvttf</description>
      <pubDate>Tue, 28 Oct 2008 12:04:47 +0000</pubDate>
      <guid>http://twitter.com/FreeGroup/statuses/978829929</guid>
      <link>http://twitter.com/FreeGroup/statuses/978829929</link>

    </item></channel></rss>
        ";
            XPathDocument doc = new XPathDocument(new StringReader(xml));
            XPathNavigator nav = doc.CreateNavigator();

            // Compile a standard XPath expression

            XPathExpression expr;
            expr = nav.Compile("/rss/channel/item");
            XPathNodeIterator iterator = nav.Select(expr);

            // Iterate on the node set

            try
            {
                while (iterator.MoveNext())
                {
                    XPathNavigator nav2 = iterator.Current.Clone();
                    nav2.MoveToChild("title","");
                    Console.WriteLine(nav2.Value);
                    nav2.MoveToParent();
                    nav2.MoveToChild("pubDate","");
                    Console.WriteLine(nav2.Value);

                }
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
            Console.ReadKey();



这是简的方式工作。

And this is jan's approach working

        XmlDocument doc2 = new XmlDocument();
        doc2.LoadXml(xml);
        XmlNode root = doc2.DocumentElement;

        foreach (XmlNode item in root.SelectNodes(@"/rss/channel/item"))
        {
            Console.WriteLine(item.SelectSingleNode("title").FirstChild.Value);
            Console.WriteLine(item.SelectSingleNode("pubDate").FirstChild.Value);
        }

这篇关于通过XmlReader中的XML元素解析的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆