你如何解析的IP地址字符串在C＃中的单元值？ [英] How do you parse an IP address string to a uint value in C#?

问题描述

我正在写使用Windows IP助手API的C＃代码。其中一个我想调用的函数是GetBestInterface接受一个I​​P的UINT表示。我需要的是解析IP的文本表示创建UINT表示。

I'm writing C# code that uses the windows IP Helper API. One of the functions I'm trying to call is "GetBestInterface" that takes a 'uint' representation of an IP. What I need is to parse a textual representation of the IP to create the 'uint' representation.

我发现通过谷歌的一些例子，喜欢的这一个或这一个，但我敢肯定应该有使用.NET来实现这一标准的方式。唯一的问题是，我无法找到这种标准方式。 IPAddress.Parse似乎是在正确的方向，但它并没有提供得到一个UINT表示任何方式...

I've found some examples via Google, like this one or this one, but I'm pretty sure there should be a standard way to achieve this with .NET. Only problem is, I can't find this standard way. IPAddress.Parse seems to be in the right direction, but it doesn't supply any way of getting a 'uint' representation...

还有一种方式这样使用IP助手，使用ParseNetworkString ，但同样，我宁愿使用.NET - 我相信我靠的PInvoke越少越好

There is also a way of doing this using IP Helper, using the ParseNetworkString, but again, I'd rather use .NET - I believe the less I rely on pInvoke the better.

因此，任何人在.NET中做到这一点的标准方式知道

So, anyone knows of a standard way to do this in .NET?

推荐答案

MSDN的says 的IPAddress.Address属性（返回的IP地址的数字表示）是过时的，你应该使用< A HREF =http://msdn.microsoft.com/en-us/library/system.net.ipaddress.getaddressbytes.aspx> GetAddressBytes 方法。

MSDN says that IPAddress.Address property (which returns numeric representation of IP address) is obsolete and you should use GetAddressBytes method.

您可以用下面的代码的IP地址转换为数值：

You can convert IP address to numeric value using following code:

var ipAddress = IPAddress.Parse("some.ip.address");
var ipBytes = ipAddress.GetAddressBytes();
var ip = (uint)ipBytes [3] << 24;
ip += (uint)ipBytes [2] << 16;
ip += (uint)ipBytes [1] <<8;
ip += (uint)ipBytes [0];

编辑：

至于其他评论者注意到上述代码是仅适用于IPv4地址。
IPv6地址为长128位，所以不可能把它转换为UINT作为问题的作者想要的。

As other commenters noticed above-mentioned code is for IPv4 addresses only. IPv6 address is 128 bits long so it's impossible to convert it to 'uint' as question's author wanted.

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