可以E4X获取父节点的属性基于对孩子的属性在任何层次？ [英] Can E4X Get Attribute of a Parent Node Based on Attribute of a Child At Any Level?

问题描述

考虑这个XML片断与节点，它可以有子节点元素无限子级别。

Consider this XML snippet with "nodes" which can have unlimited child levels of "subnode" elements.

我想找到节点对于任何给定的子节点< @type 属性/ code>，是根据它 @Id 属性。举例来说，如果我有9一个id，然后我想从上面返回值的类型=富。

I want to find @type attribute of the node for any given subnode, based on its @id attribute. For example, if I have an id of 9 then I want to return the type="foo" from above.

<xml>
    <node type="bar">
        <subnode id="4">
            <subnode id="5"/>
        </subnode>  
        <subnode id="6"/>
    </node>
    <node type="foo">
        <subnode id="7">
            <subnode id="8">
                <subnode id="9"/>
            </subnode>
        </subnode>
        <subnode id="10"/>
    </node>
</xml>

在E4X我想出了，但失败是：

The E4X I have come up with, but which fails is:

xml.node.(subnode.(@id == '8')).@type 

那种

我明白为什么这是行不通的。什么更有意义的是以下但语法失败（在AS3）：

I can kind of see why it doesn't work. What would make more sense is the following but the syntax fails (in AS3):

xml.node.(..subnode.(@id == '8')).@type

如何才能做到这一点？

How can this be done?

推荐答案

您应该能够得到使用这种E4X的类型值：

You should be able to get the type value using this E4X:

xml.node.(descendants("subnode")[e-mail]("8")).@type;

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