如何不实现类的接口的功能？ [英] How not to implement a function of an interface in class?

问题描述

这是面试官问我在采访中以下问题，但我不知道这可能是这个问题，请帮助！

An interviewer asked me the following question in interview, but I don't know what could be the answer of this question, please help!!!

如果我不想
落实在我班上一个函数，
是由我的类实现
接口中声明必须做什么。

What must be done if i don't want to implement a function in my class that is declared in an interface which is implemented by my class.

编辑：我使用与C＃.NET。这将是巨大的，如果任何人都可以提供C＃示例代码示例。

Edited: I am using .NET with C#. It will be great if anyone can provide a sample code example in C#.

感谢

推荐答案

在实施执行的功能，但抛出一个异常

Implement the function, but throw an exception in the implementation.

在.NET中，您通常使用的一下面（有其他语言类似的异常类型）。

In .NET, you typically use one of the following (there are similar exception types in other languages).

• 的 NotImplementedException ：目前的没有的方法的实现

引发NotSupportedException ：目前的不会的这个类中的方法的实现，由设计。这个多次出现在基类中，在派生类中，预计在适用情况下，提供一个实现虚拟方法。它也出现在显式接口实现方法（←这是具体的事情面试官问），如 ReadOnlyCollection还< T> 实施的ICollection< T>。新增等

NotSupportedException: There will not be an implementation of the method in this class, by design. This appears several times in virtual methods of a base class, where a derived class is expected to offer an implementation where applicable. It also appears in explicit interface implementation methods (← this is the specific thing the interviewer asked), such as the ReadOnlyCollection<T> implementation of ICollection<T>.Add, etc.

例如，在C＃中：

public void MyNotSupportedInterfaceMethod()
{
  throw new NotImplementedException();
}

更新：由于马科斯指出，如果你的类是抽象的，你可以离开实施继承人，但你还是要声明它：

UPDATE: as marcos points out, if your class is abstract, you can leave the implementation to the inheritor, but you still have to declare it:

public abstract class MyClass : ISomeInterface
{
   public abstract void MyNotImplementedInterfaceMethod();
}

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