线程和C＃中的静态方法 [英] Threading and static methods in C#

问题描述

下面是一个毫无意义的扩展方法为例：

Here is a meaningless extension method as an example:

public static class MyExtensions
{
    public static int MyExtensionMethod(this MyType e)
    {
        int x = 1;
        x = 2;

        return x
    }
}

说执行的线程完成高达并包括行：

Say a thread of execution completes upto and including the line:

x = 2; 

然后，处理器上下文切换，而另一个线程进入相同的方法，并完成行：

The processor then context switches and another thread enters the same method and completes the line:

int x = 1;

我是在假定变量x的创建，并通过第一线程分配的校正是在一独立的堆栈X创建，由第二分配，这意味着该变量此方法重入？

Am I correct in assuming that the variable "x" created and assigned by the first thread is on a separate stack to the variable "x" created and assigned by the second, meaning this method is re-entrant?

推荐答案

是的，每个线程都有自己独立的局部变量。这个函数总是返回2，即使叫同时被多个线程。

Yes, each thread gets its own separate local variable. This function will always return 2 even if called by multiple threads simultaneously.

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