如何获得在C＃中的连续字符？ [英] How to get continuous characters in C#?

问题描述

我有个

List<String> MyList=new List<string>();

我需要填写名单 MYLIST 与 N 值。

如果n的值为2则列表 MYLIST 将包含

if the value of n is 2 then the list MyList will contain

"A","B"

如果10然后

"A","B","C"....."J"

如果30然后

"A"....."Z","AA","AB",AC","AD"

如果1000然后

"A",....."Z","AA","AB"......"AZ","BA","BB"......."BZ"........"YZ","AAA",AAB".....
and so on

我不知道如何做到这一点。

I do not know how to do this.

请帮我这个使用使用任何方法来做 LINQ 或 lambda表达式

Please help me to do this using any method Using LINQ or LAMBDA Expression

推荐答案

修改2

这可能是实现它最简单的方法。我测试了它，它工作正常。你可以生成字符串的无限数量

This is probably the easiest way to implement it. I tested it, it works fine. You could generate a infinite number of strings.

public IEnumerable<string> GenerateStrings()
{
    foreach(string character in Alphabet())
    {
      yield return character;
    }

    foreach (string prefix in GenerateStrings())
    {
      foreach(string suffix in Alphabet())
      {
        yield return prefix + suffix;
      }
    }
}

public IEnumerable<string> Alphabet()
{
    for(int i = 0; i < 26; i++)
    {
      yield return ((char)('A' + i)).ToString();
    }
}

---

东西我以前写的：

---

Stuff I wrote before:

您也可以写一个小递归函数返回一个特定的指数的字符串。这可能不是最优的性能明智的，因为有一些重复的部门，但它可能是你的目的不够快。

You could also write a little recursive function which returns any string by a certain index. This may not be optimal performance wise, because there are some repetitive divisions, but it may be fast enough for your purpose.

这是很短，容易：

string GetString(int index)
{
  if (index < 26)
  {
    return ((char)('A' + index)).ToString();
  }
  return GetString(index / 26 - 1) + GetString(index % 26);
}

使用（也可放入另一种方法：

usage (may also be put into another method:

List<string> strings = Enumerable.Range(0, 1000)
  .Select(x => GetString(x))
  .ToList();

这是工作的代码，只是写了一个测试为它

This is working code, just wrote a test for it.

编辑：例如，全LINQ办法的GetString的应用程序：

eg, the "full linq way" application of GetString:

public void IEnumerale<string> GenerateStrings()
{
  int index = 0;
  // generate "infinit" number of values ...
  while (true)
  {
     // ignoring index == int.MaxValue
     yield return GetString(index++);
  }
}

List<string> strings = GenerateStrings().Take(1000).ToList();

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