显式实现接口的使用自动属性 [英] Explicit implementation of an interface using an automatic property

问题描述

有什么办法，明确实现接口使用自动的财产？例如，考虑下面的代码：

Is there any way to implement an interface explicitly using an automatic property? For instance, consider this code:

namespace AutoProperties
{
    interface IMyInterface
    {
        bool MyBoolOnlyGet { get; }
    }

    class MyClass : IMyInterface
    {
        static void Main(){}

        public bool MyBoolOnlyGet { get; private set; } // line 1
        //bool IMyInterface.MyBoolOnlyGet { get; private set; } // line 2
    }
}

此代码编译。但是，如果你有2号线更换1号线就不能编译。

This code compiles. However, if you replace line 1 with line 2 it does not compile.

（这并不是说我需要得到2号线的工作 - 我只是好奇）

(It's not that I need to get line 2 working - I'm just curious.)

推荐答案

实际上，该特定排列（用自动实现属性显式实现一个get-只接口属性的）不被支持的语言。所以的或者的做手工（与字段），或写私人自动实现的道具，和代理它。不过说实话，你的时间这样做，你还不如用一个字段...

Indeed, that particular arrangement (explicit implementation of a get-only interface property by an automatically implemented property) isn't supported by the language. So either do it manually (with a field), or write a private auto-implemented prop, and proxy to it. But to be honest, by the time you've done that you might as well have used a field...

private bool MyBool { get;set;}
bool IMyInterface.MyBoolOnlyGet { get {return MyBool;} }

或

private bool myBool;
bool IMyInterface.MyBoolOnlyGet { get {return myBool;} }

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