AddOutParameter - DBType.Int32的发现长度的非幻数的方法 [英] AddOutParameter - non-magic number way of finding length of DBType.Int32

问题描述

我在下面的代码一个神奇的数字...

I have a magic number in the following code...

Microsoft.Practices.EnterpriseLibrary.Data.Database db = /* code omitted */;

db.AddOutParameter(command, "@ParamName", DbType.Int32, 8);

有没有干净的方式来获得 DbType.Int32 ，因为所需的最后一个参数 AddOutParameter ？

Is there a clean way to get the length of DbType.Int32, as required for the last argument to AddOutParameter?

推荐答案

不知道你的意思是什么长度。这是一个32位的int所以它的4个字节可以是从的这个 MSDN页面。的整型表示与-2147483648和2147483647之间的值符号的32位整数。的

Not sure what you mean about length. It's a 32 bit int so it's 4 bytes which can be 10 digits as described in this quote from this MSDN page. An integral type representing signed 32-bit integers with values between -2147483648 and 2147483647.

我不知道帽子的指定大小（ 8 ）的一个Int32是有道理的。例如，如果它应该映射到Oracle 编号为8的指定大小大概应 DbType.Decimal 而不是的Int32。

I'm not sure hat specifying the size (the 8) for an int32 makes sense. For example, if it should map to an Oracle Number with a specified size of 8 it should probably be DbType.Decimal rather than Int32.

我会建议寻找到刚刚取出8完全因为它是一个输出参数，我不认为这会影响什么。

I'd suggest looking into just removing the 8 altogether since it's an output parameter I don't think it would affect anything.

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