你怎么能得到包含在双位数？ [英] How can you get the number of digits contained in a double?

问题描述

我试图让数字在下面的双重价值数：56.46855976不用将其转换为一个字符串（和单纯用，代替。）。

I'm trying to get the number of digits in the following double value: 56.46855976 without using converting it to a string (and simply replacing the "." with a "").

任何人有什么想法？

干杯

推荐答案

怎么算的时候，你必须在10，直到它小于1把数 - >，让您在小数点前面的数字

Count how often you must divide the number by 10 until it's smaller than 1 -> that gives you the digits before the decimal point.

再算上多久您必须通过10，直到它等于Math.Floor，结果乘以原来的号码 - >，让你的小数点后面的数字

Then count how often you must multiply the original number by 10 until it equals the Math.Floor-result -> that gives you the digits behind the decimal points.

添加。 。很高兴

修改：由于乔伊指出的，是它的一些uncertianity。定义数字的最大数量事先让你不创建一个无限循环。
在另一方面 - ？多久是丹麦海岸...

Edit: As Joey points out, there is some uncertianity in it. Define a maximum number of digits beforehand so you don't create an infinite loop. On the other hand - "How long is the coast of Denmark?"...

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