重构我的代码：在派生类中避免铸造 [英] Refactor my code : Avoiding casting in derived class

问题描述

首先，我觉得标题很抱歉，我不知道如何准确地描述我的问题。我希望这将是更好的通过代码解释

Firstly, I feel sorry about the title, I do not know how to describe my problem exactly. I hope it will be better explained through the code.

public abstract class AB {
  public MyModel Model;
}

public class A : AB {
  public A() {
    Model = new MyModelA();
  }

  public void AMethod() {
    var model = (MyModelA) model; // I have to do this all place
  }

  public void AnotherMethod() {
    var model = (MyModelA) model; // same here
    model.NewInt = 123;
  }
}

public abstract class MyModel {

}

public class MyModelA : MyModel {
  // new properties
  public int NewInt {get;set;}
}

看看代码，以便使用从派生类新的属性，我必须做一个铸件，但它是丑陋的，当我不得不使用它同时全国各地的地方。

Take a look at the code, in order to use new properties from derived class, I have to do a cast but it is ugly when I have to use it same time all over places.

我想的方法是声明另一个属性：公共MyModelA _TMP 然后我投它在构造 _TMP =（MyModelA）型号并使用它，而不是模型。

The method I think is declare another property: public MyModelA _tmp then I cast it in the constructor _tmp = (MyModelA) Model and use it instead of Model.

还有没有其他适当的方式做到这一点？
谢谢

Are there any other appropriate ways to do this ? Thanks !

推荐答案

您可以使基类通用的：

public abstract class ServiceBase<TModel> where TModel : new() {
    protected ServiceBase() { Model = new TModel(); }
    public TModel Model { get; private set; }
}

public class AService : ServiceBase<MyModelA> {
    ...
}

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