C＃ - XML - 从某个元素作为字符串对待内部XML [英] C# - XML - Treat inner xml from a certain element as string

问题描述

我有下面的XML：

<Plan>
<Error>0</Error>
<Description>1</Description>
<Document>
  <ObjectID>06098INF1761320</ObjectID>
  <ced>109340336</ced>
  <abstract>DAVID STEVENSON</abstract>
  <ced_a />
  <NAM_REC />
  <ced_ap2 />
</Document>
</Plan>

我这个反序列化：

I deserialize it with this:

[XmlRoot("Plan")]
    public class EPlan
    {
        [XmlElement("Error")]
        public string Error { get; set; }

        [XmlElement("Description")]
        public string Description { get; set; }

        [XmlElement("Document")]
        public List<EDocument> Documents { get; set; }
    }

    public class EDocument
    {
        [XmlText]    
        public string Document { get; set; }   
    }

问题是我想要的元素一号文件包含其内XML作为一个字符串，我的意思是，对象应该具有以下值：

The issue is that I want the element "Document" to contain its inner XML as a single string, I mean, the object should have these values:

obj.Error = "0";
obj.Description = "1";
obj.Documents[0].Document = "<ObjectID>06098INF1761320</ObjectID><ced>109340336</ced><abstract>DAVID STEVENSON</abstract><ced_a /><NAM_REC /><ced_ap2 />";

不过，我前面提到的方式保持检索NULL文档属性。

But the way I mentioned before keeps retrieving a NULL "Document" property.

是否可以达到我想要的行为？任何帮助，将不胜感激。

Is it possible to achieve the behaviour I want? Any help would be appreciated.

推荐答案

XMLTEXT 需要一个文本节点，但你有什么实际上是元素节点。我不知道是否有这样做直接的方式，但你可以有一个 XmlAnyElement将节点收集反序列化的结果，事后你在一个将它们合并字符串如果这是你所需要的，如下面的例子。

XmlText expects a text node, but what you have are actually element nodes. I don't know if there's a direct way to do that, but you can have a XmlAnyElement node to collect the result of the deserialization, and afterwards you merge them in a single string if that's what you need, as shown in the example below.

    [XmlRoot("Plan")]
    public class EPlan
    {
        [XmlElement("Error")]
        public string Error { get; set; }

        [XmlElement("Description")]
        public string Description { get; set; }

        [XmlElement("Document")]
        public List<EDocument> Documents { get; set; }
    }

    [XmlType]
    public class EDocument
    {
        private string document;

        [XmlAnyElement]
        [EditorBrowsable(EditorBrowsableState.Never)]
        public XmlElement[] DocumentNodes { get; set; }

        [XmlIgnore]
        public string Document
        {
            get
            {
                if (this.document == null)
                {
                    StringBuilder sb = new StringBuilder();
                    foreach (var node in this.DocumentNodes)
                    {
                        sb.Append(node.OuterXml);
                    }

                    this.document = sb.ToString();
                }

                return this.document;
            }
        }
    }

    static void Test()
    {
        string xml = @"<Plan>
  <Error>0</Error>
  <Description>1</Description>
  <Document>
    <ObjectID>06098INF1761320</ObjectID>
    <ced>109340336</ced>
    <abstract>DAVID STEVENSON</abstract>
    <ced_a />
    <NAM_REC />
    <ced_ap2 />
  </Document>
  <Document>
    <ObjectID>id2</ObjectID>
    <ced>ced2</ced>
    <abstract>abstract2</abstract>
    <ced_a />
    <NAM_REC />
    <ced_ap2 />
  </Document>
</Plan>";
        XmlSerializer xs = new XmlSerializer(typeof(EPlan));
        MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(xml));
        EPlan obj = xs.Deserialize(ms) as EPlan;
        Console.WriteLine(obj.Documents[0].Document);
    }

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