如何发送和接收1024位？ [英] How to send and receive 1024 Bits?
问题描述
我使用C＃Windows窗体设计一个界面，我想发送和接收使用串行端口1024位，我要送的数字是十六进制形式，所以我所做的就是下一个：
I'm designing an interface using C# windows Forms and I want to send and receive 1024 bits using serial port, the number I'm sending is in the hex-form, so what I did was the next:
private void button2_Click(object sender, EventArgs e)
{
int i;
int a = 0;
byte[] mychar;
mychar = new byte[128];
string M = textBox1.Text;
for (i = 0; i < 127; i++ )
{
mychar[i] = Convert.ToByte((M.Substring(a,2)),16);
a += 2;
}
serialPort1.Write(mychar,0,127);
}
和检查数据正确与否，我短路了两个发射器和接收器，让我可以看到textbox5中显示我从TextBox1中送什么，问题是显示输出为ASCII文本框，我不能告诉如何将其转换为十六进制形式，（见我的尝试是评论波纹管）：
and to check if the data is correct or not, I shorted out both the transmitter and receiver so I can see what I send from textbox1 to be shown in textbox5, the problem is the textbox is shown the output as ASCII, and I couldn't tell how to convert it to Hex form ,(see my attempt as commented bellow):
private void displaytext(object s, EventArgs e)
{
textBox5.Clear();
textBox5.AppendText(RXstring);
//int value = Convert.ToInt32(RXstring, 16);
//string stringValue = Char.ConvertFromUtf32(value);
//textBox4.AppendText(stringValue);
}
所以为总结一下我的问题：
1是要发送的数据是正确的代码？
2 - 我如何可以强制文本框来显示输出为十六进制？
so to summarize my problems: 1- Is the code to send data is correct? 2- How can I force the textbox to show the output as Hex?
非常感谢你。
更新这是我的全部代码，也许你明白我的问题：
UPDATE this is my full code, maybe then you understand my problem :
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form3 : Form
{
public Form3()
{
InitializeComponent();
}
string RXstring = "";
private void serialPort1_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
{
try
{
RXstring = serialPort1.ReadExisting();
this.Invoke(new EventHandler(displaytext));
}
catch (System.TimeoutException)
{
}
}
private void displaytext(object s, EventArgs e)
{
textBox5.Clear();
textBox5.AppendText(RXstring);
//int value = Convert.ToInt32(RXstring, 16);
//string stringValue = Char.ConvertFromUtf32(value);
//textBox4.AppendText(stringValue);
}
private void pictureBox2_Click(object sender, EventArgs e)
{
serialPort1.Close();
Form1 myForm = new Form1();
this.Close();
}
private void button1_Click(object sender, EventArgs e)
{
try
{
if (!serialPort1.IsOpen)
{
serialPort1.Open();
button1.Enabled = false;
}
else
{
MessageBox.Show("Port is Open by other party!");
}
}
catch (UnauthorizedAccessException ex)
{
MessageBox.Show(ex.Message);
}
}
private void Form3_FormClosed(object sender, FormClosedEventArgs e)
{
serialPort1.Close();
}
private void button3_Click(object sender, EventArgs e)
{
textBox1.Text = "0";
textBox2.Text = "0";
textBox3.Text = "0";
textBox4.Text = "0";
textBox5.Text = "";
}
private void button2_Click(object sender, EventArgs e)
{
int i;
int a=0;
byte[] mychar;
mychar = new byte[128];
string M = textBox1.Text;
for (i = 0; i < 127; i++ ) {
mychar[i] = Convert.ToByte((M.Substring(a,2)),16);
a += 2;
}
serialPort1.Write(mychar,0,127);
}
}
}
当我从TextBox1中发送数据我想显示正是我在textbox5发送，你可以帮我吗？
https://drive.google.com/file/d / 0B5PXKMhwKWQRREtuMXBaZDA1LUU /视图USP =共享
when I send data from textbox1 I want to be shown exactly as I send it in textbox5, can you help me in that ? https://drive.google.com/file/d/0B5PXKMhwKWQRREtuMXBaZDA1LUU/view?usp=sharing
推荐答案
我只是添加下面的代码：
I just added the following to the code :
string hex = "";
foreach (char c in RXstring)
{
int tmp = c;
hex += String.Format("{0:X2}", (uint)System.Convert.ToUInt32(tmp.ToString()));
}
textBox5.AppendText(hex);
感谢您的任何方式：）
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