如何使Windows总是在最上层的应用 [英] How to make Windows Always on top application

问题描述

我想打一个小软件，它可以提供窗口运行的应用程序，以总在最前面功能，如Linux终端提供，VLC媒体播放器等
我发现与此相关的互联网上的某些应用。但我想在上面实用程序始终创建我自己的。

I want to make a small software which can provide the windows running applications to "always on top functionality" as available in Linux terminal, VLC media player etc. I have found some application related to this on internet. but i want to create my own always on top utility.

这将是更好的，如果ü可以建议C＃.NET代码。和IDE：我会喜欢的Visual Studio

It will be better if u can suggest c# .net code. and IDE: i will prefer Visual Studio

我的目标是使应用程序如下所示：

My goal is to make the application as shown here:

< A HREF =http://www.pcworld.com/article/218511/Windows.html相对=nofollow> http://www.pcworld.com/article/218511/Windows.html

推荐答案

有关使它通用于所有的过程，你必须重载User32.dll中的两种方法是Win32 API中的一部分

For making it generic to any process, you have to overload two methods of the User32.dll which is a part of Win32 API.

只要使用如下的代码，并没有它的扩展名指定您的进程名，说了VLC - 指定

Just use the code given below and specify your process name without its extension, say for vlc - specify

processName =VLC; 和 NOT LIKE vlc.exe

public class ProcessManager
{
    [DllImport("user32.dll")]
    private static extern bool ShowWindow(IntPtr hWnd, uint windowStyle);

    [DllImport("user32.dll")]
    private static extern bool SetWindowPos(IntPtr hWnd, IntPtr hWndInsertAfter, int x, int y, int cx, int cy, uint uFlags);

    ProcessManager()
    {
      string processName = /* Your process name here */
      SearchProcessAndModifyState(processName)
    }

    void SearchProcessAndModifyState(string targetProcessName)
    {
        Process specifiedProcess = null;
        Process[] processes = Process.GetProcesses();
        for (int i = 0; i < processes.Length; i++)
        {
            Process process = processes[i];
            if (process.ProcessName == targetProcessName)
            {
                specifiedProcess = process;
                break;
            }
        }
        if (specifiedProcess != null)
        {
          ProcessManager.ShowWindow(specifiedProcess.MainWindowHandle, 1u);
          ProcessManager.SetWindowPos(specifiedProcess.MainWindowHandle, new IntPtr(-1), 0, 0, 0, 0, 3u);
        }
    }
}

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