可以DebuggerStepThrough被继承到自动生成的IEnumerable实现？ [英] Can DebuggerStepThrough be inherited into the automatically generated IEnumerable implementation?

问题描述

借助 DebuggerStepThrough 属性你可以跳过闯入某些方法/班/属性。

The DebuggerStepThrough attribute allows you to skip breaking into certain methods/classes/properties.

在 DebuggerStepThrough被忽略它阐明了C＃编译器不会继承该属性为生成的的IEnumerable<编译器; T> 的实施。

In DebuggerStepThrough being ignored it is clarified that the c# compiler does not inherit this attribute into the compiler generated IEnumerable<T> implementation.

这种故障的简单的例子是：

A trivial example of such a failure is:

static void Main(string[] args)
{
    var a = SkipMe().ToList();
}

[System.Diagnostics.DebuggerStepThrough]
static IEnumerable<int> SkipMe()
{
    // comment out line below and the throw will be stepped over.
    yield return 1;
    throw new Exception();
}

有没有办法让C＃编译器添加 DebuggerStepThrough 属性自动生成的类型？

Is there a way to get the C# compiler to add the DebuggerStepThrough attribute to the auto generated type?

有没有办法让视觉工作室跳过调试到任何类型的 [编译器生成] 属性？

Is there a way to get visual studio to skip debugging into any types with the [CompilerGenerated] attribute?

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附录：一些说明性的截图

Addendum: some illustrative screenshots

按<大骨节病> F5

Visual Studio的版本：

Visual Studio Version:

我们的遗漏属性：

推荐答案

我不认为有一种方法可以实现你要找的效果。

I don't think there is a way to achieve the effect you're looking for.

• 有没有办法让C＃编译器复制这个属性到生成状态机的方法。


• 您不能解决此加入 DebuggerStepThrough 含有迭代器方法的类获得。调试器仅着眼于眼前的父类型不包含嵌套类型的类型。

• There is no way to make the C# compiler copy this attribute into the generate state machine method.
• You can't get around this by adding DebuggerStepThrough to the class containing the iterator method. The debugger only looks at the immediate parent type not the types containing a nested type.

我能想到的，实现的唯一途径这是把所有你不想调试代码到一个单独的DLL。那就不要加载PDB为特定的DLL。

The only real way I can think of to achieve this is to put all of the code you don't want to debug into in a separate DLL. Then don't load the PDB for that particular DLL.

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