我可以做一个类型"除了内部类型和QUOT密封; [英] Can I make a type "sealed except for internal types"

问题描述

我想使可以从通过类型相同的组件被继承一个类型，但不能从该组件的外继承。我想要的类型是装配的外部可见的。

I want to make a type that can be inherited from by types in the same assembly, but cannot be inherited from outside of the assembly. I do want the type to be visible outside of the assembly.

这可能吗？

推荐答案

您可以构造内部：

public class MyClass
{
    internal MyClass() { }
}

这从一个基类派生的每个类必须调用在其构造基类的构造函数。因为它不能调用构造函数，如果基类是在不同的装配，派生类不进行编译。

Every class that derives from a base class must call a constructor of the base class in its constructor. Since it can't call the constructor if the base class is in a different assembly, the derived class doesn't compile.

这篇关于我可以做一个类型"除了内部类型和QUOT密封;的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！