为什么C＃编译器发出的IL额外的操作码？ [英] Why does C# compiler emit additional OpCodes in IL?

问题描述

如果我有一个方法乘定义为：

If I've a method Multiply defined as:

public static class Experiment
{
    public static int Multiply(int a, int b)
    {
        return a * b;
    }
}

那么为什么编译器发出此IL：

Then why does the compiler emit this IL:

.method public hidebysig static int32 Multiply(int32 a, int32 b) cil managed
{
    .maxstack 2              //why is it not 16?
    .locals init (
        [0] int32 CS$1$0000) //what is this?
    L_0000: nop              //why this?
    L_0001: ldarg.0 
    L_0002: ldarg.1 
    L_0003: mul 
    L_0004: stloc.0          //why this?
    L_0005: br.s L_0007      //why this?
    L_0007: ldloc.0          //why this?
    L_0008: ret 
}

正如你所看到的，它也包含了一些额外的操作码不道理给我的时候，其实我期待以下的IL：

As you can see, it also contains some additional OpCodes which don't make sense to me, when in fact I expect the following IL:

.method public hidebysig static int32 MyMethod(int32 a, int32 b) cil managed
{
    .maxstack 16
    L_0000: ldarg.0 
    L_0001: ldarg.1 
    L_0002: mul 
    L_0003: ret 
}

这做同样的事情。

所以，问题是，为什么编译器发出额外的操作码的IL？

So the question is, why does the compiler emit additional OpCodes in IL?

我使用调试模式。

推荐答案

多数用于调试和放大器;支持断点;看到这里的答案：的为什么我的调试这些NOP指令建立？

Mostly for debugging & breakpoint support; See an answer here: Why are these nop instructions in my debug build?

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