使用拉姆达C＃泛型出口的ForEach [英] c# exit generic ForEach that use lambda

问题描述

有谁知道是否有可能退出使用拉姆达一个通用的ForEach？例如：

Does anyone know if it is possible to exit a generic ForEach that uses lambda? e.g.

someList.ForEach(sl =>
  {
    if (sl.ToString() == "foo")
        break;

    // continue processing sl here
    // some processing code
  }
);

这代码本身将无法编译。我知道我可以使用一个普通的foreach，但为了保持一致性我想使用的lambda。

This code itself won't compile. I know I could use a regular foreach but for consistency I want to use lambda.

非常感谢。

推荐答案

当然。但首先，请注意，我建议对本;我说一个序列运营商应该不会有副作用，并且声明应该有一个副作用。如果你在这的ForEach拉姆达做一些事情，然后使它在foreach循环体，而不是使它看起来像一个序列运算符的声明。

Sure. But first, note that I recommend against this; I say that a sequence operator should not have a side effect, and a statement should have a side effect. If you're doing something in that ForEach lambda, then make it a statement in the body of a foreach loop rather than making it look like a sequence operator.

这说，这里是你做了什么。首先，你自己写的任意序列的作品一个foreach，而不是仅仅列出：

That said, here's what you do. First, you write yourself a ForEach that works on arbitrary sequences, not just lists:

public static void ForEach<T>(this IEnumerable<T> sequence, Action<T> action)
{
    foreach(var item in sequence) action(item);
}

和现在你写你的休息是这样的：

And now you write your break like this:

someList
    .TakeWhile(x=>x.ToString() != "foo")
    .ForEach(sl=>
    {/*your action here*/});

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