如何计算两个整数的相似性？ [英] How do I calculate similarity of two integers?

问题描述

其实这是相当难来形容：结果
我想要实现它通过在同一位置的图对比图（因为我做我在基于10系统计算，这是相当相同的权力的算法的的两个给定的整数/数字（具有相同）长度）十位。它应该返回平等的等级如下：

• 4491和1020 = 0


• 4491及4123 = 1


• 4491和4400 = 2


• 4491及4493 = 3


• 4491及4491 = 4


• 4491及4091 = 1

我不希望我的计算基础上做一个字符串比较，因为我会在某种程度上这样做更大的情景：）

解决方案

 公共静态INT比较（INT I1，I2 INT）
 {
 INT结果= 0; 
，而（I1 = 0&安培;！&安培;！I2 = 0）
 {
 VAR D1 = I1％10; 
 VAR D2 = I2％10; 
的i1 / = 10; 
 I2 / = 10; 
如果（D1 D2 = =）
 {
 ++的结果; 
} 
，否则
 {
结果为0; 
} 
} 
如果（I1！= 0 || I2！= 0）
 {
抛出新的ArgumentException（整数必须相同的长度。） ; 
} 
返回结果; 
} 
  

请注意：它不处理负整数

更新：固定的问题，更新后

Actually it's quite hard to describe:
I want to implement an algorithm which compares figure by figure of the same position (as I do my calculations in a 10-based system it's rather the same "power of ten") of two given integers/number (with the same "length"). It should return the grade of equality as following:

• 4491 and 1020 = 0
• 4491 and 4123 = 1
• 4491 and 4400 = 2
• 4491 and 4493 = 3
• 4491 and 4491 = 4
• 4491 and 4091 = 1

I do not want to do my calculations based on a string-comparison, as I'll doing this in a way bigger scenario :)

解决方案

public static int Compare(int i1, int i2)
{
    int result = 0;
    while(i1 != 0 && i2 != 0)
    {
        var d1 = i1 % 10;
        var d2 = i2 % 10;
        i1 /= 10;
        i2 /= 10;
        if(d1 == d2)
        {
            ++result;
        }
        else
        {
            result = 0;
        }
    }
    if(i1 != 0 || i2 != 0)
    {
        throw new ArgumentException("Integers must be of same length.");
    }
    return result;
}

Note: it does not handle negative integers

Update: fixed after question update

这篇关于如何计算两个整数的相似性？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！