定时器，鼠标​​，鼠标按下，鼠标松开事件不是一起工作 [英] Timer, click, mousedown, mouseup events not working together

问题描述

寻找一个问题进出口有

对不起，如果这个问题已经被问，我找不到类似的事情。

$ B $一些帮助b

我们的想法是，当点击一个图片被改变图像为ON。

如果图片框保持超过2秒开一种新的形式，并留下该图片为OFF。

但是，如果图片框上点击，然后保持2秒钟，然后返回我需要的PictureBox的状态留在。

下面是我到目前为止已经试过。

我相信这正常工作，我需要停下来从发生的历史MouseUp事件。

有没有一种方式，当勾选时我可以停止的MouseUp？

有没有更简单/更好的方式来做到这一点？

任何帮助，将不胜感激。

 私人无效time_HoldDownInternal_Tick（对象发件人，EventArgs五）
 {
 time_HoldDownInternal.Enabled = FALSE; 
 time_HoldDownInternal.Interval = 1000; 
 form1show.Visible = TRUE; 
} 
 
私人无效pb_pictureBoxTest_MouseDown（对象发件人，MouseEventArgs E）
 {
 mainMenuVariables.mousedown = TRUE; 
 time_HoldDownInternal.Enabled = TRUE; 
} 
 
私人无效pb_pictureBoxTest_MouseUp（对象发件人，MouseEventArgs E）
 {
 mainMenuVariables.mousedown = FALSE; 
 //MessageBox.Show(\"mouse了）; 
 time_HoldDownInternal.Enabled = FALSE; 
 time_HoldDownInternal.Interval = 1000; 
} 
 
私人无效pb_pictureBoxTest_Click（对象发件人，EventArgs五）
 {
如果（mainMenuVariables.mousedown ==真）
 {
如果（mainMenuVariables.pictureBox ==假）
 {
 mainMenuVariables.pictureBox = TRUE; 
 pb_pictureBoxTest.Image =新位图（mainMenuVariables.pictureBoxOn）; 
的回报; 
} 
如果（mainMenuVariables.pictureBox ==真）
 {
 mainMenuVariables.pictureBox = FALSE; 
 pb_pictureBoxTest.Image =新位图（mainMenuVariables.pictureBoxOff）; 
的回报; 
} 
} 
如果（mainMenuVariables.mousedown ==假）
 {
 //什么
} 
} 
  

解决方案

而不是启动一个定时器，只是记录鼠标当前的时间了。然后在小鼠，检查它是否已经2秒。例如：

 私人无效pb_pictureBoxTest_MouseDown（对象发件人，MouseEventArgs E）
 {
 mainMenuVariables.mousedown = TRUE ; 
 mainMenuVariables.mousedowntime = DateTime.Now; 
} 
 
私人无效pb_pictureBoxTest_MouseUp（对象发件人，MouseEventArgs E）
 {
 mainMenuVariables.mousedown = FALSE; 
 VAR clickDuration = DateTime.Now  -  mainMenuVariables.mousedowntime; 
 
如果（clickDuration> TimeSpan.FromSeconds（2））
 {
 //做'持有'逻辑（例如，开放的对话，等等）
} 
，否则
 {
 //完成正常的逻辑点击（如切换开/关的图像）
} 
} 
  

Looking for some help on a problem Im having

sorry if this question has already been asked, I can not find anything similar.

The idea is when a picturebox is clicked changed the image to ON.

If the picture box is held for more than 2 seconds to open a new form and leave the picturebox as OFF.

However if the picturebox is clicked ON and then held for 2 seconds and then returns i need the picturebox state to remain ON.

Here is what I have tried so far.

I believe for this to work correctly I need to stop MouseUp event from occuring.

Is there a way I can stop MouseUp when Tick occurs?

Is there a easier / better way to do this?

Any help would be appreciated.

    private void time_HoldDownInternal_Tick(object sender, EventArgs e)
    { 
        time_HoldDownInternal.Enabled = false;
        time_HoldDownInternal.Interval = 1000;
        form1show.Visible = true;
    }

    private void pb_pictureBoxTest_MouseDown(object sender, MouseEventArgs e)
    {
        mainMenuVariables.mousedown = true;
        time_HoldDownInternal.Enabled = true;
    }

    private void pb_pictureBoxTest_MouseUp(object sender, MouseEventArgs e)
    {
        mainMenuVariables.mousedown = false;
        //MessageBox.Show("mouse up");
        time_HoldDownInternal.Enabled = false;
        time_HoldDownInternal.Interval = 1000;
    }

    private void pb_pictureBoxTest_Click(object sender, EventArgs e)
    {
        if (mainMenuVariables.mousedown == true)
        {
            if (mainMenuVariables.pictureBox == false)
            {
                mainMenuVariables.pictureBox = true;
                pb_pictureBoxTest.Image = new Bitmap(mainMenuVariables.pictureBoxOn);
                return;
            }
            if (mainMenuVariables.pictureBox == true)
            {
                mainMenuVariables.pictureBox = false;
                pb_pictureBoxTest.Image = new Bitmap(mainMenuVariables.pictureBoxOff);
                return;
            }
        }
        if (mainMenuVariables.mousedown == false)
        {
            //nothing
        }
    }

解决方案

Rather than starting a timer, just record the current time on mouse down. Then in mouse up, check if it has been 2 seconds. e.g:

private void pb_pictureBoxTest_MouseDown(object sender, MouseEventArgs e)
{
    mainMenuVariables.mousedown = true;
    mainMenuVariables.mousedowntime = DateTime.Now;
}

private void pb_pictureBoxTest_MouseUp(object sender, MouseEventArgs e)
{
    mainMenuVariables.mousedown = false;
    var clickDuration = DateTime.Now - mainMenuVariables.mousedowntime;

    if ( clickDuration > TimeSpan.FromSeconds(2))
    {
        // Do 'hold' logic (e.g. open dialog, etc)
    }
    else
    {
        // Do normal click logic (e.g. toggle 'On'/'Off' image)
    }
}

这篇关于定时器，鼠标​​，鼠标按下，鼠标松开事件不是一起工作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！