使用随机数在一个列表中选择一个项目并将其移动到另一个列表 [英] Using random numbers to select a item in one list and move it to another list

问题描述

我设计的卡片游戏叫四合（继承人呈现规则的链接 HTTP： //boardgames.about.com/od/cardgames/a/snap.htm ），在我的版本中，玩家将在中间点击桩，如果对显示出来。我目前4类，一个用于存储卡（其是称为cardValue_ INT），一个用于玩家手，一个用于卡的原甲板和一个用于卡在中间堆。因此，甲板，桩手类有卡在其中一个列表。现在我试图写它包含卡的列表甲板类洗牌方法。这将选择一个随机卡并将其移动到一个新的列表，直到所有的卡片摘下来，然后再回到原来的列表，从而做一个简单的洗牌。我的方法，到目前为止是这样的...

I am designing a card game called Snap (Heres a link showing rules http://boardgames.about.com/od/cardgames/a/snap.htm), in my version, the player will have to click on the pile in the middle if a pair shows up. I have 4 classes currently, one for the card (which is a int called cardValue_), one for the players hand, one for the original deck of cards and one for the pile of cards in the middle. So the Deck, Pile and Hand classes has a List of Cards in them. I am now trying to write a shuffle method for the Deck class which contains a list of Cards. Which will pick a random card and move it to a new list until all the cards are picked, then move them back to the original list, thus doing a simple shuffle. My method so far looks like this...

public List<Deck> Shuffle(List<Card> cardDeck)
    {
        int index = 0;
        Random randomCard = new Random();
        List<Card> newDeck = new List<Card>();

        while (index < cardDeck.Count)
        {
            int ran = randomCard.Next(0, cardDeck.Count);
            foreach (Card card in cardDeck)
            {

            }
        }
    }

我试图找出哪些应该在foreach循环中去（除非整个的方法是错误的），但现在我想我已经宣布我所有的卡在错误的的地方，所有的52张牌的形式，目前申报，或者我应该在甲板类中声明它们？

I am trying to work out what should go in the foreach loop (unless the whole method is wrong), but now I am thinking I have declared all my Cards in the wrong place, all 52 cards are currently declared in the Form, or should i be declaring them in the Deck class?

推荐答案

您在哪里相当接近，我将如何解决这个问题，我会做的就是复制出源列表中随机直到它是空的，然后只是填充它。你并不需要返回一个列表，因为这会打乱你传递列表中。

You where fairly close to how I would solve it, what I would do is copy out of the source list randomly until it is empty and then just refill it. You don't need to return a list as this will just shuffle the list you pass in.

//Move this out of the function, if you are wondering why search SO for "Not random" and choose any of the 100's of people asking "why is random not random?" :)
private static Random randomCard = new Random(); //Not thread safe, if multi-threading use locks!!!

public static void Shuffle(List<Card> cardDeck)
{
    int index = 0;
    List<Card> tempDeck = new List<Card>();

    while (cardDeck.Count > 0)
    {
        int removal = randomCard.Next(0, cardDeck.Count);
        Card tempCard = cardDeck[removal];
        cardDeck.RemoveAt(removal);
        tempDeck.Add(tempCard);
    }

    //cardDeck is empty at this point, now we refill it with our randomized deck.
    cardDeck.AddRange(tempDeck);
}

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如果你想不。修改原来的列表，你想一个新的随机名单只是第一个复制源列表

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If you want to not modify the original list and you do want a new randomized list just copy the source list first.

public static List<Card> Shuffle(List<Card> cardDeck)
{
    int index = 0;
    List<Card> tempDeck = new List<Card>();
    List<Card> localCopy = new List<Card>(cardDeck);   //Creates a shallow copy of the list.      

    while (localCopy.Count > 0)
    {
        int removal = randomCard.Next(0, cardDeck.Count);
        Card tempCard = localCopy[removal];
        localCopy.RemoveAt(removal);
        tempDeck.Add(tempCard);
    }

    return tempDeck;
}

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我会推荐使用< A HREF =http://stackoverflow.com/a/14766143/80274>理查德的方法。它要简单得多。

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