逃跑的新行字符的XmlDocument [英] Escaping new-line characters with XmlDocument

问题描述

我的应用程序中使用的XmlDocument生成一个XML。一些数据包含换行符和回车符

My application generates XML using XmlDocument. Some of the data contains newline and carriage return characters.

当文本被分配到一个XmlElement的是这样的：

When text is assigned to an XmlElement like this:

   e.InnerText = "Hello\nThere";

生成的XML看起来是这样的：

The resulting XML looks like this:

<e>Hello
There</e>

的

XML（我没有控制权）的接收器把新线为空白并看到上面的文字为：

The receiver of the XML (which I have no control over) treats the new-line as white space and sees the above text as:

 "Hello There"

有关接收方保留新线它需要的编码为：

For the receiver to retain the new-line it requires the encoding to be:

<e>Hello&#xA;There</e>

如果数据被施加到一个XmlAttribute，新线被正确编码

If the data is applied to an XmlAttribute, the new-line is properly encoded.

我试着将文本使用的InnerText和InnerXml的XmlElement但是输出上是相同的，以

I've tried applying text to XmlElement using InnerText and InnerXml but the output is the same for both.

有没有？的方式来获得的XmlElement文本节点输出的新行和回车符号在其编码的形式

Is there a way to get XmlElement text nodes to output new-lines and carriage-returns in their encoded forms?

下面是一些示例代码来演示问题：

Here is some sample code to demonstrate the problem:

string s = "return[\r] newline[\n] special[&<>\"']";
XmlDocument d = new XmlDocument();
d.AppendChild( d.CreateXmlDeclaration( "1.0", null, null ) );
XmlElement  r = d.CreateElement( "root" );
d.AppendChild( r );
XmlElement  e = d.CreateElement( "normal" );
r.AppendChild( e );
XmlAttribute a = d.CreateAttribute( "attribute" );
e.Attributes.Append( a );
a.Value = s;
e.InnerText = s;
s = s
    .Replace( "&" , "&amp;"  )
    .Replace( "<" , "&lt;"   )
    .Replace( ">" , "&gt;"   )
    .Replace( "\"", "&quot;" )
    .Replace( "'" , "&apos;" )
    .Replace( "\r", "&#xD;"  )
    .Replace( "\n", "&#xA;"  )
;
e = d.CreateElement( "encoded" );
r.AppendChild( e );
a = d.CreateAttribute( "attribute" );
e.Attributes.Append( a );
a.InnerXml = s;
e.InnerXml = s;
d.Save( @"C:\Temp\XmlNewLineHandling.xml" );

该程序的输出是：

<?xml version="1.0"?>
<root>
  <normal attribute="return[&#xD;] newline[&#xA;] special[&amp;&lt;&gt;&quot;']">return[
] newline[
] special[&amp;&lt;&gt;"']</normal>
  <encoded attribute="return[&#xD;] newline[&#xA;] special[&amp;&lt;&gt;&quot;']">return[
] newline[
] special[&amp;&lt;&gt;"']</encoded>
</root>

提前

感谢。
克里斯。

Thanks in advance. Chris.

推荐答案

<击>如何使用 HttpUtility.HtmlEncode（）结果
的http：// MSDN。 microsoft.com/en-us/library/73z22y6h.aspx

确定，很抱歉的错误领导那里。 HttpUtility.HtmlEncode（）将不可以处理你所面临的新行问题。

OK, sorry about the wrong lead there. HttpUtility.HtmlEncode() will not handle the newline issue you're facing.

这个博客链接将会帮助你，尽管

的 http://weblogs.asp.net/mschwarz/archive/2004/02/16/73675.aspx

This blog link will help you out, though
http://weblogs.asp.net/mschwarz/archive/2004/02/16/73675.aspx

基本上，换行符处理由 XML控制：空间=保存属性

Basically, the newline handling is controlled by the xml:space="preserve" attribute.

样品工作代码：

XmlDocument doc = new XmlDocument();
doc.LoadXml("<ROOT/>");
doc.DocumentElement.InnerText = "1234\r\n5678";

XmlAttribute e = doc.CreateAttribute(
    "xml", 
    "space", 
    "http://www.w3.org/XML/1998/namespace");
e.Value = "preserve";
doc.DocumentElement.Attributes.Append(e);

var child = doc.CreateElement("CHILD");
child.InnerText = "1234\r\n5678";
doc.DocumentElement.AppendChild(child);

Console.WriteLine(doc.InnerXml);
Console.ReadLine();

输出将读取：

<ROOT xml:space="preserve">1234
5678<CHILD>1234
5678</CHILD></ROOT>

这篇关于逃跑的新行字符的XmlDocument的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！