waveout的与WaveOutEvent [英] WaveOut versus WaveOutEvent

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本文介绍了waveout的与WaveOutEvent的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我用 n音讯

WaveOutEvent Klangwiedergabegeraet;

private void Play(string Dateiname)
{
    Klangwiedergabegeraet = new WaveOutEvent();
    Klangwiedergabegeraet.DeviceNumber = comboBox1.SelectedIndex;
    ISampleProvider StueckchenHalter = null;
    StueckchenHalter = CreateInputStreamS(Dateiname);
    Klangwiedergabegeraet.Init(new SampleToWaveProvider(StueckchenHalter));  
    Klangwiedergabegeraet.Play();
}

private void Cancel()
{
    if (Klangwiedergabegeraet != null)
    {
        Klangwiedergabegeraet.Stop();
        Klangwiedergabegeraet.Dispose();
    }
}



在运行时取消() ,它不会停止。当我用

When running Cancel(), it won't stop. When I used

WaveOut Klangwiedergabegeraet;

private void Play(string Dateiname)
{
    Klangwiedergabegeraet = new WaveOut();
    ...
}

private void Cancel()
{
    if (Klangwiedergabegeraet != null)
    {
        Klangwiedergabegeraet.Stop();
        Klangwiedergabegeraet.Dispose();
    }
}



它的工作。这是为什么,什么改变?

It worked. Why is this and what to change?

PS 我使用 WaveOutEvent 而不是 waveout的,因为 waveout的没有属性 DeviceNumber

P.S I am using WaveOutEvent instead of WaveOut because WaveOut does not have the property DeviceNumber.

推荐答案

如果您是在非GUI线程中运行,那么 WaveOutEvent 是推荐的方式来做事,而不是 waveout的因为这会选择函数回调可以是一些声卡不可靠的。此外, waveout的的确有 DeviceNumber 属性。

If you are running on a non-GUI thread, then WaveOutEvent is the recommended way to do things, not WaveOut as that will choose function callbacks which can be unreliable on some soundcards. Also, WaveOut does have a DeviceNumber property.

这篇关于waveout的与WaveOutEvent的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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