如何从文本框传递一个值作为参数，以行动 [英] How to pass a value from TextBox as parameter to Action

问题描述

这就是我脑子里想的，但当然这是行不通的。

This is what I've had in mind but of course it doesn't work.

@{
    var textBoxData = form.find('input[name="textboxList"]').val();
 } 
<input type="button" value="Add"  title="Add"  onclick="location.href='@Url.Action("Create_Add", "Controller", new { textboxList = textBoxData })'" />

我应该如何传递呢？控制器操作名称和参数是否正确。只是，我不知道如何在文本框中输入的值...

How should I pass this? Controller action name and parameter are correct. Just that I don't know how to get the value entered in textbox...

我有保存表单中的表单麻烦，所以有人建议此解决方案。代理代码是：

I have trouble with saving a form within a form, so someone suggested this solution. Proxy code would be:

<firstForm>
   textboxfor Name
   dropdownfor DType

   If DTypeDDL value is "List" then
       <secondForm>
            textboxfor nameOfItem
            submitSecondForm (using that method i mentioned above)
       </secondForm>
   End If

   submitFirstForm
</firstForm>

我一直在试图挽救2形式的相当长一段时间，但现在没有运气。这基本上是我的最后一招。

I've been trying to save 2 forms for quite a while now but no luck. This is basically my last resort.

推荐答案

首先，你应该有一个视图模型面向HTML文件去，因为你正在使用MVC （模型的，视图，控制器）：

First of all, you should go with a viewmodel oriented html file since you are using MVC (Model, View, Controller):

创建一个视图模型：

public class ExampleViewModel
{
    public ExampleViewModel()
    {
    }

    public virtual string TextBoxData { get; set; }
}

后，代码中使用的视图模型为模型的HTML：

After, code your html using the viewmodel as model:

@model Models.Views.ExampleViewModel
@using (Html.BeginForm())
{
<div class="editor-row">
        <div class="editor-label">
            @Html.LabelFor(model => model.TextBoxData)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.TextBoxData)
        </div>
</div>
<input type="submit" value="submit" />
}

和控制器：

public ActionResult Example()
{
    ExampleViewModel model = new ExampleViewModel();
    return This.View(model);
}

[HttpPost]
public ActionResult Example(ExampleViewModel model)
{
    string infoEntered = model.TextBoxData;
    // Do something with infoEntered
}

的东西

希望这会帮助你！

Hope this will help you!

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