当反序列化JSON响应时，RestSharp客户端将返回所有属性为null [英] RestSharp client returns all properties as null when deserializing JSON response

问题描述

我试图做一个非常简单的例子，使用RestSharp的Execute方法查询一个休息端点和序列化到一个POCO。

这里是JSON响应：

  {
Result：
 {
Location：
 {
BusinessUnit ：BTA，
BusinessUnitName：CASINO，
LocationId：4070，
LocationCode：ZBTA，
LocationName：赌场名称
} 
} 
} 
  

我的测试代码

  [TestMethod] 
 public void TestLocationsGetById（）
 {
 // given 
 var request = new RestRequest（）; 
 request.Resource = serviceEndpoint +/ {singleItemTestId}; 
 request.Method = Method.GET; 
 request.AddHeader（accept，Configuration.JSONContentType）; 
 request.RootElement =Location; 
 request.AddParameter（singleItemTestId，singleItemTestId，ParameterType.UrlSegment）; 
 request.RequestFormat = DataFormat.Json; 
 
 //当
时位置位置= api.Execute< Location>（request）; 
 
 // then 
 Assert.IsNotNull（location.LocationId）; // failed  -  all properties are returned null 
 
} 
  

我的API代码

  public T Execute< T>（RestRequest request）其中T：new（）
 {
 var client = new RestClient（）; 
 client.BaseUrl = Configuration.ESBRestBaseURL; 
 
 //request.OnBeforeDeserialization = resp => {resp.ContentLength = 761; }; 
 
 var response = client.Execute< T>（request）; 
 return response.Data; 
} 
  

最后，这里是我的POCO

  public class Location 
 {
 public string BusinessUnit {get;组; } 
 public string BusinessUnitName {get;组; } 
 public string LocationId {get;组; } 
 public string LocationCode {get;组; } 
 public string LocationName {get;组; } 
} 
  

此外，响应中的ErrorException和ErrorResponse属性为NULL。

这看起来是一个非常简单的例子，但我一直在运行在全天！感谢。

解决方案

响应中的 Content-Type 是什么？如果不是像application / json这样的标准内容类型，则RestSharp不会理解哪个解串器使用。如果事实上RestSharp不能理解一个内容类型（您可以通过检查请求中发送的 Accept 来验证），那么您可以通过执行以下操作来解决这个问题： / p>

  client.AddHandler（my_custom_type，new JsonDeserializer（））; 
  

编辑：

好的，对不起，再次查看JSON，你需要像：

  public class LocationResponse 
 public LocationResult Result {get;组; } 
} 
 
 public class LocationResult {
 public Location Location {get;组; } 
} 
  

然后执行：

$ b b

  client.Execute< LocationResponse>（request）; 
  

I'm trying to do a very simple example of using RestSharp's Execute method of querying a rest endpoint and serializing to a POCO. However, everything I try results in a response.Data object that has all properties with a NULL value.

Here is the JSON response:

{
   "Result":
   {
       "Location":
       {
           "BusinessUnit": "BTA",
           "BusinessUnitName": "CASINO",
           "LocationId": "4070",
           "LocationCode": "ZBTA",
           "LocationName": "Name of Casino"
       }
   }
}

Here is my test code

 [TestMethod]
    public void TestLocationsGetById()
    {
        //given
        var request = new RestRequest();
        request.Resource = serviceEndpoint + "/{singleItemTestId}";
        request.Method = Method.GET;
        request.AddHeader("accept", Configuration.JSONContentType);
        request.RootElement = "Location";
        request.AddParameter("singleItemTestId", singleItemTestId, ParameterType.UrlSegment);
        request.RequestFormat = DataFormat.Json;

        //when
        Location location = api.Execute<Location>(request);            

        //then
        Assert.IsNotNull(location.LocationId); //fails - all properties are returned null

    }

And here is my API code

 public T Execute<T>(RestRequest request) where T : new()
    {
        var client = new RestClient();
        client.BaseUrl = Configuration.ESBRestBaseURL;

        //request.OnBeforeDeserialization = resp => { resp.ContentLength = 761; };

        var response = client.Execute<T>(request);
        return response.Data;
    }

And finally, here is my POCO

 public class Location
{        
    public string BusinessUnit { get; set; }
    public string BusinessUnitName { get; set; }
    public string LocationId { get; set; }
    public string LocationCode { get; set; }
    public string LocationName { get; set; }
}

Additionally, the ErrorException and ErrorResponse properties on the response are NULL.

This seems like a very simple case, but I've been running around in circles all day! Thanks.

解决方案

What is the Content-Type in the response? If not a standard content type like "application/json", etc. then RestSharp won't understand which deserializer to use. If it is in fact a content type not "understood" by RestSharp (you can verify by inspecting the Accept sent in the request), then you can solve this by doing:

client.AddHandler("my_custom_type", new JsonDeserializer());

EDIT:

Ok, sorry, looking at the JSON again, you need something like:

public class LocationResponse
   public LocationResult Result { get; set; }
}

public class LocationResult {
  public Location Location { get; set; }
}

And then do:

client.Execute<LocationResponse>(request);

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