在Linux中用C ++代码清除终端 [英] Clearing terminal in Linux with C++ code

问题描述

好吧，我一直在研究如何做到这一点，但说我正在运行一个程序，在终端上有一大堆输出，我如何清除屏幕从我的程序，以便我可以保持我的程序运行？

我知道我可以在终端输入清除，它清除得很好，但就像我说的，对于这个程序，它会对我更有利。 p>

我发现了一些有用的东西，但我不知道是什么或它做什么。

  cout<< \ 033 [2J\033 [1; 1H; 
  

这可行，但我不知道是什么，如果你能解释它，非常感谢。

解决方案

这些是ANSI转义码。第一个（ \033 [2J ）从上到下清除整个屏幕（ J c $ c> 2 ）。第二个代码（ \033 [1; 1H ）将光标置于行 1 <>

所有ANSI转义都以 ESC [具有由; 分隔的零个或多个参数，并以命令字母（ J 和 H ）结尾。 \033 是转义字符的C样式八进制序列。

请参阅此处查看完整路演。

Okay, I have been researching on how to do this, but say I am running a program that has a whole bit of output on the terminal, how would I clear the screen from within my program so that I can keep my program running?

I know I can just type clear in terminal and it clears it fine, but like I said, for this program it would be more benefitial for me.

I found something that works, however, I'm not sure what it is or what its doing.

cout << "\033[2J\033[1;1H";

That works but I have no clue what it is, if you could explain it, than I would much appreciate it.

解决方案

These are ANSI escape codes. The first one (\033[2J) clears the entire screen (J) from top to bottom (2). The second code (\033[1;1H) positions the cursor at row 1, column 1.

All ANSI escapes begin with the sequence ESC[, have zero or more parameters delimited by ;, and end with a command letter (J and H in your case). \033 is the C-style octal sequence for the escape character.

See here for the full roadshow.

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