隐式转换和显式转换之间的差异 [英] Difference between implicit conversion and explicit conversion

问题描述

可能重复：

Implicit VS Explicit Conversion

和显式转换？

推荐答案

显式转换是使用一些语法来 em>程序做一个转换。例如（在Java中）：

An explicit conversion is where you use some syntax to tell the program to do a conversion. For example (in Java):

int i = 999999999;
byte b = (byte) i;  // The type cast causes an explicit conversion
b = i;              // Compilation error!!  No implicit conversion here.

隐式转换是指没有任何语法的转换。例如（在Java中）：

An implicit conversion is where the conversion happens without any syntax. For example (in Java):

int i = 999999999;
float f = i;    // An implicit conversion is performed here

通常涉及表示的一些改变，并且可能导致精度的损失或信息的丢失。相比之下，涉及参考类型（仅）的转换不会更改基本表示。

It should be noted that (in Java) conversions involving primitive types generally involve some change of representation, and that may result in loss of precision or loss of information. By contrast, conversions that involve reference types (only) don't change the fundamental representation.

Java和C ++中的区别是不同的吗？

Is the difference different in Java and C++?

我不这么想。显然，可用的转换将是不同的，但是隐式和显式之间的区别将是相同的。 （注意：我不是C ++语言的专家...但是这些单词在英语中有一个自然的含义，我不能想象C ++规范在矛盾的意义上使用它们。）

I don't imagine so. Obviously the conversions available will be different, but the distinction between "implicit" and "explicit" will be the same. (Note: I'm not an expert on the C++ language ... but these words have a natural meaning in English and I can't imagine the C++ specifications use them in a contradictory sense.)

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