如何从stdin编译代码？ [英] How to compile code from stdin?

问题描述

代码很简单：

  test $ cat test.cpp 
 
 int main ）
 {
} 
  

有一种方法可以编译代码

  
 cat test.cpp | g ++  -  
  

和一些变体，但没有生成可执行文件。

---

只是一些澄清。我有一个程序，它预处理一个文件，并产生另一个文件，我想编译。我想不要创建这个中间文件，而是直接生成对象文件。

解决方案

编译器可能会告诉你：

 当从标准输入输入时需要-E或-x 
  pre> 
 
 
尝试
  cat test.cpp | g ++ -x c ++  -  
  
 
The code is quite simple :
test$ cat test.cpp

int main()
{
}
Is there a way to compile the code that is coming from a standard output?

I have tried this :
cat test.cpp | g++ -
and some variations, but none produced executable.



Just some clarifications. I have a program which preprocess a file, and produces another file which I want to compile. I thought about not creating this intermediate file, but to instead produce the object file directly.
解决方案
The compiler would have probably told you:
-E or -x required when input is from standard input
Try
cat test.cpp | g++ -x c++ -


                        
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