Java和C ++操作符之间有什么区别吗？ [英] Is there any difference between the Java and C++ operators?

问题描述

如果你使用Java的原始数字类型，加上布尔值，并将其与C ++等价类型进行比较，是否存在与运算符有关的任何差异，如优先规则或位操作运算符？或者括号的效果？

If you take Java's primitive numeric types, plus boolean, and compare it to C++ equivalent types, is there any difference what concerns the operators, like precedence rules or what the bit-manipulation operators do? Or the effect of parenthesis?

另一种方式，如果我拿一个Java表达式，并试图编译和运行它在C + +，它总是编译，总是给同样的

Asked another way, if I took a Java expression and tried to compile and run it in C++, would it always compile and always give the same result?

推荐答案

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  • For an expression like:

    a = foo() + bar();
    

    在Java中，评估顺序已明确定义（从左到右）。 C ++不指定是否先评估 foo（）或 bar（）。

    In Java, the evaluation order is well-defined (left to right). C++ does not specify whether foo() or bar() is evaluated first.

    喜欢：

    i = i++;
    

    在C ++中未定义，但在Java中也已定义好。

    is undefined in C++, but again well-defined in Java.

    在C ++中，对负数执行右移是实现定义的/未定义的;

    In C++, performing right-shifts on negative numbers is implementation-defined/undefined; whereas in Java it is well-defined.

    此外，在C ++中，运算符& | 和 ^ 是纯位运算符。在Java中，根据上下文，它们可以是按位或逻辑运算符。

    Also, in C++, the operators &, | and ^ are purely bitwise operators. In Java, they can be bitwise or logical operators, depending on the context.

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