提交表单与AJAX传递表单数据到PHP无刷新页面 [英] Form submit with AJAX passing form data to PHP without page refresh

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本文介绍了提交表单与AJAX传递表单数据到PHP无刷新页面的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

谁能告诉我为什么code此位是不工作?

Can anyone tell me why this bit of code isn't working?

<html>
  <head>
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <script>
      $(function () {
        $('form').bind('submit', function () {
          $.ajax({
            type: 'post',
            url: 'post.php',
            data: $('form').serialize(),
            success: function () {
              alert('form was submitted');
            }
          });
          return false;
        });
      });
    </script>
  </head>
  <body>
    <form>
      <input name="time" value="00:00:00.00"><br>
      <input name="date" value="0000-00-00"><br>
      <input name="submit" type="button" value="Submit">
    </form>
  </body>
</html>

当我把提交什么也没有发生。在接收php文件我用$ _ POST ['时间']和$ _ POST ['日']把数据在一个MySQL查询,但它只是没有得到数据。有什么建议么?我假设它的东西做的提交按钮,但我不能算出它

When I push submit nothing happens. In the receiving php file I'm using $_POST['time'] and $_POST['date'] to put the data in a mysql query but it's just not getting the data. Any suggestions? I'm assuming it's something to do with the submit button but I can't figure it out

推荐答案

该表单Ajax请求后提交。

The form is submitting after the ajax request.

<html>
  <head>
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <script>
      $(function () {

        $('form').on('submit', function (e) {

          e.preventDefault();

          $.ajax({
            type: 'post',
            url: 'post.php',
            data: $('form').serialize(),
            success: function () {
              alert('form was submitted');
            }
          });

        });

      });
    </script>
  </head>
  <body>
    <form>
      <input name="time" value="00:00:00.00"><br>
      <input name="date" value="0000-00-00"><br>
      <input name="submit" type="submit" value="Submit">
    </form>
  </body>
</html>

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