如何以编程方式获取Linux中目录的可用磁盘空间 [英] How do I programmatically get the free disk space for a directory in Linux
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问题描述
是否有一个函数返回给定目录路径的驱动器分区上有多少空间?
解决方案
code> man statvfs(2)
我相信你可以计算'free space'为
f_bsize * f_bfree
。 NAME
statvfs,fstatvfs - 获取文件系统统计信息
SYNOPSIS
#include< sys / statvfs.h>
int statvfs(const char * path,struct statvfs * buf);
int fstatvfs(int fd,struct statvfs * buf);
DESCRIPTION
函数statvfs()返回已装入文件系统的相关信息。
path是装入的文件系统中任何文件的路径名。 buf
是一个指向statvfs结构的指针,大致定义如下:
struct statvfs {
unsigned long f_bsize; / *文件系统块大小* /
unsigned long f_frsize; / * fragment size * /
fsblkcnt_t f_blocks; / * f_frsize单位中fs的大小* /
fsblkcnt_t f_bfree; / *#free blocks * /
fsblkcnt_t f_bavail; / *#空闲块用于非特权用户* /
fsfilcnt_t f_files; / *#inodes * /
fsfilcnt_t f_ffree; / *#free inodes * /
fsfilcnt_t f_favail; / *#免费inode为无特权的用户* /
unsigned long f_fsid; / *文件系统ID * /
unsigned long f_flag; / * mount flags * /
unsigned long f_namemax; / *最大文件名长度* /
};
Is there a function that returns how much space is free on a drive partition given a directory path?
解决方案
check man statvfs(2)
I believe you can calculate 'free space' as f_bsize * f_bfree
.
NAME
statvfs, fstatvfs - get file system statistics
SYNOPSIS
#include <sys/statvfs.h>
int statvfs(const char *path, struct statvfs *buf);
int fstatvfs(int fd, struct statvfs *buf);
DESCRIPTION
The function statvfs() returns information about a mounted file system.
path is the pathname of any file within the mounted file system. buf
is a pointer to a statvfs structure defined approximately as follows:
struct statvfs {
unsigned long f_bsize; /* file system block size */
unsigned long f_frsize; /* fragment size */
fsblkcnt_t f_blocks; /* size of fs in f_frsize units */
fsblkcnt_t f_bfree; /* # free blocks */
fsblkcnt_t f_bavail; /* # free blocks for unprivileged users */
fsfilcnt_t f_files; /* # inodes */
fsfilcnt_t f_ffree; /* # free inodes */
fsfilcnt_t f_favail; /* # free inodes for unprivileged users */
unsigned long f_fsid; /* file system ID */
unsigned long f_flag; /* mount flags */
unsigned long f_namemax; /* maximum filename length */
};
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