jQuery的AJAX调用PHP脚本使用JSON返回 [英] jQuery AJAX Call to PHP Script with JSON Return

问题描述

我一直在砸我的头撞墙用这个，我已经尝试了解决方案的计算器上的负荷，但不能找到一个工程！

I've been smashing my head against a brick wall with this one, i've tried loads of the solutions on stackoverflow but can't find one that works!

基本上当我后我的AJAX的PHP返回JSON但AJAX显示未定义的而不是值：

Basically when I POST my AJAX the PHP returns JSON but the AJAX shows Undefined instead of the value:

JS

  /* attach a submit handler to the form */
  $("#group").submit(function(event) {

  /* stop form from submitting normally */
  event.preventDefault();

  /*clear result div*/
  $("#result").html('');

  /* get some values from elements on the page: */
  var val = $(this).serialize();

  /* Send the data using post and put the results in a div */
  $.ajax({
      url: "inc/group.ajax.php",
      type: "post",
      data: val,
  datatype: 'json',
      success: function(data){
            $('#result').html(data.status +':' + data.message);   
            $("#result").addClass('msg_notice');
            $("#result").fadeIn(1500);           
      },
      error:function(){
          $("#result").html('There was an error updating the settings');
          $("#result").addClass('msg_error');
          $("#result").fadeIn(1500);
      }   
    }); 
});

PHP

  $db = new DbConnector();
  $db->connect();
  $sql='SELECT grp.group_id, group_name, group_enabled, COUNT('.USER_TBL.'.id) AS users, grp.created, grp.updated '
        .'FROM '.GROUP_TBL.' grp '
        .'LEFT JOIN members USING(group_id) '
        .'WHERE grp.group_id ='.$group_id.' GROUP BY grp.group_id';

    $result = $db->query($sql);     
    $row = mysql_fetch_array($result);
    $users = $row['users'];
    if(!$users == '0'){
        $return["json"] = json_encode($return);
        echo json_encode(array('status' => 'error','message'=> 'There are users in this group'));
    }else{

        $sql2= 'DELETE FROM '.GROUP_TBL.' WHERE group_id='.$group_id.'';
        $result = $db->query($sql2);

        if(!$result){
            echo json_encode(array('status' => 'error','message'=> 'The group has not been removed'));
        }else{
            echo json_encode(array('status' => 'success','message'=> 'The group has been removed'));
        }
    }

从萤火 JSON结果

{"status":"success","message":"success message"}

AJAX显示JSON结果是不确定的，我没有一个线索，为什么。我曾尝试显示添加的dataType =json的和数据类型='json的。我自己也尝试将其更改为 data.status 和数据['状态'] ：仍然没有喜悦，虽然。

AJAX Displays the JSON result as Undefined and I dont have a clue why. I have tried displaying adding dataType='json' and datatype='json'. I have also tried changing it to data.status and data['status']: still no joy though.

任何帮助将是非常美联社preciated。

Any help would be really appreciated.

推荐答案

请它的dataType ，而不是的数据类型。

和PHP中添加以下code作为Ajax请求期待JSON和不接受任何东西，但JSON。

And add below code in php as your ajax request is expecting json and will not accept anything, but json.

header('Content-Type: application/json');

正确的内容类型，JSON和JSONP

在萤火可见的反应是文本数据。检查内容类型响应头进行验证，如果响应是JSON。它应该是应用程序/ JSON 为数据类型：JSON和的text / html 为数据类型：HTML

The response visible in firebug is text data. Check Content-Type of the response header to verify, if the response is json. It should be application/json for dataType:'json' and text/html for dataType:'html'.

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