我应该送一个AJAX请求有何反应/状态code时，有一个用户/表单验证错误？ [英] What response/status code should I send to an AJAX request when there is a user/form validation error?

问题描述

我创建，用户可以在编辑就地的记录，并通过AJAX提交表单使用jQuery我的web应用程序的功能。

I am creating a feature of my web application where a user can "edit-in-place" a record and submit the form via AJAX using jQuery.

当有人阿贾克斯编辑的纪录，他们用有效的数据提交表单，我送一个200状态code，从而引发了jQuery AJAX成功的功能，则忽略响应主体（因为它是成功的，我并不需要它），并折叠的形式。

When someone is "ajax editing" a record and they submit the form with valid data, I send a 200 status code, which triggers the jQuery AJAX Success function, then ignore the response body (since it was successful, I don't need it), and collapse the form.

当有校验错误，我送一个400状态code，以触发jQuery的错误方法，并在请求的主体我指定的字段不验证。

When there are form validation errors, I send a 400 status code in order to trigger the jQuery error method, and in the body of the request I specify which fields did not validate.

在一个previous StackOverflow上的问题，有人提到，似乎有些奇怪，我是发送400状态code和响应主体工作。是我的方法不是最好的做法？你有什么建议，我做这种情况呢？

In a previous StackOverflow question, someone mentioned that it "seemed odd" that I was sending a 400 status code and working with the response body. Is my approach not a best-practice? What would you recommend that I do in this situation?

推荐答案

使用的4XX状态code中的有效载荷就好了。有没有在HTTP规范说并非如此。

Using the payload of a 4xx status code is just fine. There's nothing in the HTTP spec saying otherwise.

如果你想要的东西比400更具体，看看 422不能处理实体

If you want something more specific than 400, have a look at 422 Unprocessable Entity.

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